cgo: Is it possible to make exported function have __stdcall calling convention?
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Konstantin Khomoutov
Oct 29, 2022, 8:23:36 AM10/29/22
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Hi!
I have a need to create a Windows i386 DLL whose exported functions have
__stdcall calling convention - this is the requirement of the piece of
software which is to load and call this DLL; we cannot change the caller, and
have to adapt to its requirements.
The only approach I was able to find so far is to export the Go function under
a different name and have a separate C file with an adapter function declared
as __stdcall, which calls the target Go function. For instance, this approach
is detailed in [1].
The question: is there a more direct approach? Is it somehow possible to tell
cgo to generate the wrapper for the exported function as using __stdcall
calling convention (as such a wrapper is generated anyway)?
1. https://github.com/golang/go/issues/32851#issuecomment-507017147
I have a need to create a Windows i386 DLL whose exported functions have
__stdcall calling convention - this is the requirement of the piece of
software which is to load and call this DLL; we cannot change the caller, and
have to adapt to its requirements.
The only approach I was able to find so far is to export the Go function under
a different name and have a separate C file with an adapter function declared
as __stdcall, which calls the target Go function. For instance, this approach
is detailed in [1].
The question: is there a more direct approach? Is it somehow possible to tell
cgo to generate the wrapper for the exported function as using __stdcall
calling convention (as such a wrapper is generated anyway)?
1. https://github.com/golang/go/issues/32851#issuecomment-507017147
Ian Lance Taylor
Oct 29, 2022, 10:34:09 AM10/29/22
to golang-nuts
As far as I know that is the only way.
Ian
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