escaping unix filename for bash invocation

[gocss]

Is there a function that I can pass a unix filename string too
which will escape characters that may cause issues when invoking bash ??

example filename: 12%3!4"3 '< [> 3 |.txt

gocss

l

[Marvin Stenger]

You are fine to backslash escape every character, so I guess you can implement a function for yourself easily.

[Shawn Milochik]

On Tue, Dec 8, 2015 at 7:39 PM, Marvin Stenger <marvin.s...@gmail.com> wrote:

You are fine to backslash escape every character, so I guess you can implement a function for yourself easily.

I don't know if that's the best solution for this, but if it solves the problem, you can just use strings.Split and strings.Join to do it:

http://play.golang.org/p/h6HPIfHsod

[Jesse McNelis]

It's best to avoid invoking a shell if you can, much better to just
invoke the programs you want to run directly from Go.
If you're invoking programs directly from Go then you won't need to
escape the filename. You can just pass it in as an arg.

[Paul Borman]

It really depends on what you are trying to do with the file name, as indicated by other posters.  If you really are creating a command line that is to be directly parsed by bash then you can put the name in single quotes for the most part.  The exception is if you want a single quote, but that is not hard.  If you have the name %bob's file then it would become  '%bob'"'"'s file'.  See http://play.golang.org/p/ntk8EEGjfk for an example of how to do that.  But are you really sure you need to do this?

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[Tong Sun]

Thanks Paul, that's exactly what I really need to do.