inverse of time.Duration?

[Hemant Singh]

This is an example of time.Duration I have: 5.671msec

I need to convert the duration to rate = 1.0/5.671 msec.

However, time.Duration and float in 1.0 do not mix.  How do I get the rate?

thanks,

Hemant

[Michael Jones]

start := time.Now()

:

// work to be timed

:

elapsed := time.Now().Sub(start).Seconds()

hertz := 1.0/elapsed

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[Burak Serdar]

According to the docs, Duration is nanoseconds in int64. So this should work:

rate=1.0/double(dur)

The result would be in 1/nsecs

[Sam Whited]

On Fri, Feb 15, 2019, at 20:00, Burak Serdar wrote:
> rate=1.0/double(dur)

nit: s/double/float64/

—Sam

[Burak Serdar]

oops. Thanks for the correction.

>
> —Sam

[Hemant Singh]

Thanks all. I figured it out too, but using sprintf and strconv.Atoi.

Best.

Hemant

[Louki Sumirniy]

time.Duration is nanoseconds. You can easily get any other unit by dividing by the time.Timeunit by another time unit.(time.Minute time.Second, time.Millisecond, time.Microsecond)

If that 1 in your formula means time.Second then you could just replace it with that, and 5.671ms would be equal to 5671 ns (er, that is if I read it correct as milliseconds, otherwise 5671*time.Millisecond). 

[simon place]

just reading this, surprised no mention of this...

d,_:=time.ParseDuration("5.671ms")
Hz:=int(time.Second/d)