Is Stack Smashing Code standard?

[DK]

The following program gives the output as the last initialized variable
in the function func. Is this type of code behaviour standard or just a
gcc quirk?

#include <iostream>
using namespace std;
int func(int);
int main() {
int n = func(2);
cout << n << endl;
return 0;
}
int func(int a) {
int b = a*a;
int c = b*b;
}

Output: 16
Thanks in advance.

[jacob navia]

DK a écrit :

This is undefined behavior. You fail to specify the return value.
Anything can happen, including (but not limited to)
returning the last value used.

[Paul Pluzhnikov]

jacob navia <ja...@jacob.remcomp.fr> writes:

> DK a écrit :
>> The following program gives the output as the last initialized variable
>> in the function func.

For some platforms and some versions of gcc and some compilation
options:

# Linux/x86
$ g++ -g junk.cc && ./a.out
16
$ g++ -g junk.cc -O && ./a.out
0

# Solaris/SPARC
$ g++ -g junk.cc && ./a.out
16
$ g++ -g junk.cc -O && ./a.out
2

> Anything can happen, including (but not limited to)
> returning the last value used.

And (as above) anything *does* happen ...

Cheers,
--
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