On 8/16/20 10:47 AM, Todd A. Jacobs wrote:
> The echo builtin accepts options, but does not seem to handle
> `--` correctly as the end of options.
The correct behavior for echo is described here:
"The echo utility shall not recognize the "--" argument in the manner
specified by Guideline 10 of XBD Utility Syntax Guidelines; "--" shall
be recognized as a string operand."
> The expected behavior
> would be for -- to be removed, and any following flag-like
> substrings printed as-is.
Your expectations are wrong, they contradict what POSIX says.
> echo "-n" # "" but expecting "-n"
POSIX says this one is implementation-defined; so whether -n is treated
as an option or as a string to echo has to be documented by the
implementation (bash documents treating it as an option).
> echo -- -n foo # -- -n foo
POSIX says this has to output '-- -n foo' and a newline. -n wasn't
first, so you no longer have the implementation-defined behavior, but
> echo -- "-n foo" # -- -n foo
I see nothing in your report about bash disobeying POSIX, but rather
confusion on your part about what POSIX actually requires.
Eric Blake, Principal Software Engineer
Red Hat, Inc. +1-919-301-3226