(Just attempting to keep things organized)
From Sulman:
If x is positive, is x > 4?
(1) (4 x)^2 < 1
(2) (x 4)^2 < 1
- Sulman, I'm not sure if it's just my computer, but I can't see anything in the two equations between the 4 and the x. I'll assume it's a minus sign, but correct me if I'm wrong:
Here is my approach; hopefully someone else can confirm or refute.
Rigorous Method:
(1): (4-x)^2 < 1 means that |4-x| < 1.
If x < 4, (4-x) will be positive. Thus (4-x) < 1 reduces to x > 3. In this case, 3 < x < 4.
If x > 4, (4-x) will be negative. Thus (x-4) < 1 reduces to x < 5. In this case, 4 < x < 5.
We have a case in which x > 4 is true, and a case in which x > 4 is false.
Statement 1 is therefore insufficient.
(2): (x-4)^2 < 1 means that |x-4| < 1. This will be analyzed like the last case:
If x < 4, (x-4) will be negative. Thus (4-x) < 1 reduces to x > 3. In this case, 3 < x < 4.
If x > 4, (x-4) will be positive. Thus (x-4) < 1 reduces to x < 5. In this case, 4 < x < 5.
Again, we have cases that demonstrate both truth and falsehood of the question stem.
Statement (2) is thus insufficient.
(1) + (2) together: looking at the two equations, we can see that they don't provide any extra information than either one alone. Still insufficient.
The answer is thus (E).
Simple Method:
We want to know if x > 4:
Imagine a number line: <-------------------------(4)--------------------------->
Statement 1 simply tells us the maximum distance between x and 4 is 1. <------------------------(3)///////////(4)////////////(5)----------------->
The shaded region represents the possible value for x.
Statement 2 tells us the exact same thing.
So, clearly we cannot determine whether or not x > 4.
(E).