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Re: Area problems
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Alexander Bogomolny
Jul 7, 2008, 11:21:54 AM7/7/08
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First, the function is nit "sen" but "sin".
Second, sin(45) = sqrt(2)/2 which is only approximately equals 0.707106781.
So, your formula gives:
A = 1/2 (4)(5)(sen 45) = 10 sqrt(2) / 2 = 5 sqrt(2),
as is declared in the book.
A. Bogomolny
http://www.cut-the-knot.org
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