access elements of a set to subset another set for writing equations

[Bharath K]

set G /1,4,17,18/;

set g(G);

set T;

set t(T);

param k(T);

param n(T);

equation eq1(G);

eq1(g).. sum(t$(k(t) = ord(g)) n(t) >= 10 works. But this creates 4 equations …

sum(t$(k(t) = 1), n(t)) >= 10

sum(t$(k(t) = 2), n(t)) >= 10

sum(t$(k(t) = 3), n(t)) >= 10

sum(t$(k(t) = 4), n(t)) >= 10

since ord(g) refers to position of an item in a set but I want the value of that element. How do I do that? I want 

something like ... 

eq1(g).. sum over t such that k(t)=g) n(t) >= 10  which does not work

I want eq1(g) to spawn 4 equations …

sum(t$(k(t) = 1), n(t)) >= 10

sum(t$(k(t) = 4), n(t)) >= 10

sum(t$(k(t) = 17), n(t)) >= 10

sum(t$(k(t) = 18), n(t)) >= 10

Thanks

Bharath

[Renger van Nieuwkoop]

Hi Bharath

You could use g.val(g) which gives, if the set elements are numbers, the value of the element g

Cheers

Renger

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[Bharath K]

When I rewrite the equation as follow it gives errors. Is there a syntax guidance on usage?

eq1(g).. sum(t$(k(t) = g.val(g)), n(t)) =g= 10 

Errors:
8 ')' expected
10 ',' expected
37 '=l=' or '=e=' or '=g=' operator expected

148 Dimension different - The symbol is referenced with more/less indices as declared

Thanks!

Bharath

[Renger van Nieuwkoop]

Check your parentheses for the $ statement…

[Bharath]

The issue got resolved when i used g.val instead of g.val(g) 

Thanks! 

Bharath

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