union - Bold/Underlined is a question mark

[Viral Mehta]

#include <stdio.h>

struct inside {

        int a;

        char b;

        int c;

};

struct bigger {

        struct inside in;

        int d;

};

union outside {

        struct inside in;

        struct bigger big;

};

int main()

{

        union outside out;

        out.big.in.a = 9; //ASSIGN TO BIG

        out.big.in.b = 'a';

        out.big.in.c = 10;

        out.big.d = 11;

        //GET IT FROM SMALL

        // WILL THIS ALWAYS WORK ???

        printf(" %d : %c : %d : %d\n", out.in.a, out.in.b, out.in.c, out.big.d);

}

--

Thanks,
Viral Mehta

[Vishal Thanki]

On Thu, Jul 14, 2016 at 12:15 PM, Viral Mehta <vira...@gmail.com> wrote:
> #include <stdio.h>
> struct inside {
> int a;
> char b;
> int c;
> };
>
> struct bigger {
> struct inside in;
> int d;
> };

If the members declared in "bigger" structure is shuffled (order of
declaration is changed),
it may not work.

Is that what you were looking for?

> union outside {
> struct inside in;
> struct bigger big;
> };
>
> int main()
> {
> union outside out;
>
> out.big.in.a = 9; //ASSIGN TO BIG
> out.big.in.b = 'a';
> out.big.in.c = 10;
> out.big.d = 11;
>
> //GET IT FROM SMALL
> // WILL THIS ALWAYS WORK ???
> printf(" %d : %c : %d : %d\n", out.in.a, out.in.b, out.in.c,
> out.big.d);
>
>
> }
>
>
> --
> Thanks,
> Viral Mehta
>

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[Viral Mehta]

Ah, shuffling is the condition that i did not put.... It has to be first member always...

I have seen this normally where you have same header for different operations and actual result differs for some.... In that case, you use this pattern

--

Thanks,
Viral Mehta