Richard Chivers
unread,Nov 14, 2020, 1:12:48 PM11/14/20Sign in to reply to author
Sign in to forward
You do not have permission to delete messages in this group
Either email addresses are anonymous for this group or you need the view member email addresses permission to view the original message
to Foodsa...@googlegroups.com
We are based in the UK and have a chilled storage facility that holds 1500 tonnes of fruit juices and fruit pulps, contained in double lined bags within steel barrels, at lower than 5 centigrade.
I would like to carry out a risk assessment on ambient temperature rise and its ability to raise the temperature of our product. I’m imagining complete failure of our refrigeration due to power loss. What I don’t know how to calculate is the amount of heat needed to raise the temperature of 1500 tonnes of fluid by one degree centigrade. A quick Google search told me that:
The specific heat capacity of water is 4,200 joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200J to raise the temperature of one kg of water by 1°C.
A Joule is one 3600th of a watt-hour, how do I convert that to ambient air temperature and how can I relate that to product temperature rise?
I appreciate the shape of the containers and the specific heat of the product will have an effect, but I would like to get an idea of the probability of an issue arising but at that point I became lost anyway.
As an example, I would like to be able to carry out my risk assessment and say ‘It will take X hours per degree centigrade in the ambient air to raise the temperature of 1500 tonnes of fluid by one degree.’
Can anyone give me a direction on this?
Yours hopefully,
Richard Chivers