Hi Don,
It is my understanding that the detector output voltage has already accounted for the temperature of the detector itself. The relationship between voltage and radiance is actually between delta-Voltage and delta-Radiance. So the lepton should be spitting out delta-V, rather than just V. I believe the differencing is done within the camera circuitry. I believe the way the microbolometer gets delta-V is through the calibration shutter. When the calibration is thrown, the assumption is made that the shutter is the same temperature as the rest of the microbolometer and optics housing. So the voltage at a pixel when the shutter is closed is sort of the ground state of that pixel. Then when the scene is viewed, it spits out the difference between the voltage when the shutter is closed and when it is open. (Note: I am not 100% sure that this happens in all microbolometers! That is why it is always good to let your camera warm up for a bit to reach a stable operating temperature before collecting important data. If someone is more knowledge about this, please chime in! )
Here is one useful introductory article that covers a bunch of things:
and here is a very detailed explanation of how uncooled microbolometers (like the Lepton) are calibrated:
You have a good question about using the normalized response function vs rescaling it to be "non-normalized" with some sort of transfer function. Honestly, I think that you can use it as it is presented in that document. Just multiply the planck curve by that response function, then integrate to get radiance. Using the normalized curve will create a systematic error that will be pretty well accounted for in the constants in the linear relationship relationship between voltage and radiance.
Keep in mind that you must also account for emissivity! That is why calibration is made much easier by using blackbodies.
So, for example, lets say you are trying to do a very precise calibration of your lepton. What you'll want to do is point it at something with a very high emissivity that is at a very stable, well-known temperature. Conical cavities that have been painted black work very well as blackbodies. You can rig one up with heaters and thermometers so that you can control the temperature and keep track of it precisely. Then you take a series of photos at different temperatures, calculate what the blackbody radiance was based on its known temperature from the thermometers and the camera spectral response function, then plot up your voltage and radiance points to get your response curve.
Once you have your calibration curve, you can take a measurement with the lepton and convert the voltage back to radiance. From there, you will see what temperature corresponds to that radiance. I usually just make a lookup table to radiance to temperature.
If you want me to go more in depth with emissivity, let me know. I will also try to find more literature explaining these things. Sorry I couldn't find anything better.
-Andy