Keep it Simple... FlexiGrid

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SeanJon Nay

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Jun 15, 2013, 4:46:17 PM6/15/13
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i'm trying to keep my PHP/Json simple, but not spitting out data :(


PHP:
while($Ro = $db -> fetch_assoc($Re)){ $ThisArray[] = array( 'A' => $Ro['Alliance'], 'C' => (int)$Ro['iCount'] ); }
echo json_encode($ThisArray);

JS:
$("#testtable").flexigrid({
url: 'AjaxPulls.php?get=AllianceStatus&Status=1&YAlliance=MyGuild&Terr=This&Quad=That',
dataType: 'json',
colModel : [
{display: 'Alliance', name : 'A', width : 150, sortable : true, align: 'center'},
{display: '#', name : 'C', width : 150, sortable : true, align: 'center'}
],
title: 'Our Status',
sortname: "C",
sortorder: "asc",
usepager: false,
useRp: false,
showTableToggleBtn: true,
width: 300,
height: 200
}); 

It will create the grid, but no data is shown, I checked the array, it was valid.. Am I missing something?

Serdar Sanrı

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Jun 23, 2013, 12:53:27 AM6/23/13
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You gotta use json_encode($array, true)

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