Problem with firebase function it is returned undefined value in a async function

[Javier Melo]

Hello: I am creating a function in firebase that calls other functions. This call is made asynchronously one by one. When I call the "foreachhours()" function it uses a loop to call another function called "getfilterhours()". When I bring the data from "getfilterhours()", when it is printed on screen it works correctly. But when I assign it to a variable it tells me that I need a promise, that's why there is the .then after the call. The problem is that when I return the Ddr data the result is either undefined or an empty [] array. What options do I have to return that value without it showing up with nothing?.

Thanks, for your help.

[Sam Stern]

Hi Javier,

It looks like you're mixing a few programming styles, you have async/await but also promise chaining with then/catch.  It's very likely that your flow is incorrect and this is not an issue with Firebase, although it's hard to debug code from a screenshot (please send code as text in the future).

One thing that stands out is your first function which has something like this:

await array.forEach(async function (hora) {

   await somethingElse(hora) 

});

This will not work as you expect.  You cannot await a forEach loop with an async callback.  Instead try this style:

for (const hora of horasselected) {

  await somethingElse(hora);

}

- Sam

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