Google Firestore: Query on substring of a property value (text search)

[Ruben Chevez]

I am looking to add a simple search field, would like to use something like

collectionRef.where('name', 'contains', 'searchTerm')

[Sam Stern]

Hi Ruben,

Firestore does not have full text search so this is not possible right now.  We recommend that you use an external search service, here's an example: 

https://firebase.google.com/docs/firestore/solutions/search

Sam

On Tue, May 28, 2019, 4:20 PM Ruben Chevez <rubench...@gmail.com> wrote:

I am looking to add a simple search field, would like to use something like

collectionRef.where('name', 'contains', 'searchTerm')

--
You received this message because you are subscribed to the Google Groups "Firebase Google Group" group.
To unsubscribe from this group and stop receiving emails from it, send an email to firebase-tal...@googlegroups.com.
To post to this group, send email to fireba...@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/firebase-talk/a25f513e-bca0-474d-969b-3215b30a33ed%40googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

[Ruben Chevez]

Hello Sam,

Do you know any free alternative to Angolia?

On Tuesday, 28 May 2019 13:43:50 UTC-2:30, Samuel Stern wrote:

Hi Ruben,

Firestore does not have full text search so this is not possible right now.  We recommend that you use an external search service, here's an example: 

https://firebase.google.com/docs/firestore/solutions/search

Sam

On Tue, May 28, 2019, 4:20 PM Ruben Chevez <rubench...@gmail.com> wrote:

I am looking to add a simple search field, would like to use something like

collectionRef.where('name', 'contains', 'searchTerm')

--
You received this message because you are subscribed to the Google Groups "Firebase Google Group" group.

To unsubscribe from this group and stop receiving emails from it, send an email to fireba...@googlegroups.com.

[Peter C]

If you’re not looking for a full text search (which I believe is a huge downside to firestore that it doesn’t come out of the box) then you can also use indexing with

collectionRef.where('name', “>=“, 'searchTerm')