When you say that you've assumed emissivity=1, does this mean you set EMISSIVITY=1 for the SURF that applies to where you are measuring the AST? If you didn't set a value in FDS, then the default EMISSIVITY in FDS is 0.9 and that is the value that should be used.
Below is a very simple input file. At 10 s AST=92.945 C, TG=106.585 C, h=7.142 W/m/K, and qr=0.9103 kW/m2
e ( qr - sigma AST^4) = 0.9 * (910.3 - 5.67E-8 * (273.16+92.945)^4) = -97.37 W/m2
The sum of these is 0.06 W/m2 which is ~0. It seens like the AST is working correctly. I'd suggest double checking your calculation to make sure you don't have an error. If you still have the case where your AST does not seem to be correct, submit a simple input file to the issue tracked. In this case, something like just the fire and enough of the geometry around it to contain the set of near devices.
&HEAD CHID='AST'/
&MESH XB=0,2,0,2,0,2,IJK=20,20,20/
&TIME T_END=10/
&REAC FUEL='PROPANE',SOOT_YIELD=0.02/
&SURF ID='FIRE',HRRPUA=1000,COLOR='RED'/
&VENT XB=0.4,0.6,0.4,0.6,0.0,0.0,SURF_ID='FIRE'/
&DEVC XYZ= 0.2,0.2,2.0,IOR=-3,ID='AST',QUANTITY='ADIABATIC SURFACE TEMPERATURE'/
&DEVC XYZ= 0.2,0.2,2.0,IOR=-3,ID='TG',QUANTITY='GAS TEMPERATURE'/
&DEVC XYZ= 0.2,0.2,2.0,IOR=-3,ID='h',QUANTITY='HEAT TRANSFER COEFFICIENT'/
&DEVC XYZ= 0.2,0.2,2.0,IOR=-3,ID='qr',QUANTITY='INCIDENT HEAT FLUX'/