The visibility distance is calculated by FDS by the formula:
S = C / (Km * rho * Ysoot) [in meter]
with C = 3 and Km = 8700 m²/kg by default. When there is no soot
(Ysoot=0), S should be infinity. In FDS, the maximum value for S is 30
m (arbitrary choice).
Ysoot is the local value of the mass fraction of soot (deduced from
the mixture fraction calculation: so the way you define the combustion
reaction matters ! (soot yield)).
S is the visibility distance within a homogeneous medium whose soot
concentration is Ysoot. As a consequence, this estimation is wrong for
instance if you are in a small zone without smoke which is surrounded
by smoke. In this case, you should see a kind of "smoke wall". You
have to solve the radiative transport equation to treat such a case.
Finally, I suggest you to read the following reference :
http://fire.nist.gov/bfrlpubs/fire02/PDF/f02072.pdf
Cheers
Sylvain
On 28 mai, 15:00, "
clemen...@tpi.setec.fr" <
clemen...@tpi.setec.fr>
wrote: