I can't recall on which thread I made the argument, and Clark agreed, that if the universe has a finite age, it cannot be infinite in spatial extent. In response, Clark and Brent claimed it could've began as infinite. Isn't there a theorem, which might have been proven by Penrose, that the contracting universeOnly the observable universe, if I recall correctly.
must converge to a point or zero volume containing all matter and energy? What is the name of that theorem, assuming it exists? AG --
On 2/8/2025 12:47 AM, Alan Grayson wrote:
I can't recall on which thread I made the argument, and Clark agreed, that if the universe has a finite age, it cannot be infinite in spatial extent. In response, Clark and Brent claimed it could've began as infinite. Isn't there a theorem, which might have been proven by Penrose, that the contracting universeOnly the observable universe, if I recall correctly.
On Saturday, February 8, 2025 at 3:26:33 PM UTC-7 Brent Meeker wrote:
On 2/8/2025 12:47 AM, Alan Grayson wrote:
I can't recall on which thread I made the argument, and Clark agreed, that if the universe has a finite age, it cannot be infinite in spatial extent. In response, Clark and Brent claimed it could've began as infinite. Isn't there a theorem, which might have been proven by Penrose, that the contracting universeOnly the observable universe, if I recall correctly.Applying the Penrose-Hawking Singularity Theorem, running the clock backward implies the universe doesn't converge to a point of zero volume, but to a BH, and that's the whole universe, not just the observable universe. AG
Firstly, if the age of the universe is finite, it can't expand spatially to infinity regardless of its rate of expansion. So if the universe is spatially infinite, this must have been its initial condition. Secondly, current theory is that the very very early universe was hugely hot, at a much higher temperature than at present. This implies, for me, that it was small, analogous to a highly compressed gas. IMO, it can't be small and hot, and also be spatially infinite. If it's not spatially infinite, it can't be flat. As it contracts, if it forms a singularity with all its mass and energy concentrated in a tiny region, it will presumably form a BH. Planck satelite data allows for a positively and negatively geometry, but the data for flatness is much more persuasive. I therefore believe it is so huge that we cannot distinguish between positively curved and flat. It's likely approximately spherical in shape because the expansion is approximately uniform, that is isotropic, as evidenced by the near uniformity of the Cosmological Red Shift. AGÂ
On Saturday, February 8, 2025 at 3:26:33 PM UTC-7 Brent Meeker wrote:
On 2/8/2025 12:47 AM, Alan Grayson wrote:
I can't recall on which thread I made the argument, and Clark agreed, that if the universe has a finite age, it cannot be infinite in spatial extent. In response, Clark and Brent claimed it could've began as infinite. Isn't there a theorem, which might have been proven by Penrose, that the contracting universeOnly the observable universe, if I recall correctly.
Applying the Penrose-Hawking Singularity Theorem, running the clock backward implies the universe doesn't converge to a point of zero volume, but to a BH, and that's the whole universe, not just the observable universe. AG
Brent
must converge to a point or zero volume containing all matter and energy? What is the name of that theorem, assuming it exists? AG --
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On Sunday, February 9, 2025 at 10:08:36 AM UTC-7 Jesse Mazer wrote:
Firstly, if the age of the universe is finite, it can't expand spatially to infinity regardless of its rate of expansion.
So if the universe is spatially infinite, this must have been its initial condition. Secondly, current theory is that the very very early universe was hugely hot, at a much higher temperature than at present. This implies, for me, that it was small, analogous to a highly compressed gas. IMO, it can't be small and hot, and also be spatially infinite.
If it's not spatially infinite, it can't be flat. As it contracts, if it forms a singularity with all its mass and energy concentrated in a tiny region, it will presumably form a BH.
Planck data allows for a positively and negatively geometry, but the dats for flatness is more persuasive. I believe is it so huge that we can't distinguish between positively curved and flat. It's likely approximately spherical in shape because the expansion is approximately uniform as evidenced by the near uniformity in outward expansion of the Cosmological Red Shift. AGÂ
On Sun, Feb 9, 2025 at 3:57 PM Alan Grayson <agrays...@gmail.com> wrote:On Sunday, February 9, 2025 at 10:08:36 AM UTC-7 Jesse Mazer wrote:On Sun, Feb 9, 2025 at 2:04 AM Alan Grayson <agrays...@gmail.com> wrote:On Saturday, February 8, 2025 at 3:26:33 PM UTC-7 Brent Meeker wrote:
On 2/8/2025 12:47 AM, Alan Grayson wrote:
I can't recall on which thread I made the argument, and Clark agreed, that if the universe has a finite age, it cannot be infinite in spatial extent. In response, Clark and Brent claimed it could've began as infinite. Isn't there a theorem, which might have been proven by Penrose, that the contracting universeOnly the observable universe, if I recall correctly.Applying the Penrose-Hawking Singularity Theorem, running the clock backward implies the universe doesn't converge to a point of zero volume, but to a BH, and that's the whole universe, not just the observable universe. AGThe Penrose-Hawking singularity theorems only implies an initial singularity, it doesn't say the universe was a black hole or that the whole universe (not just the observable part) must be finite--a black hole metric is different GR solution than the Friedmann–Lemaître–Robertson–Walker metric for an expanding universe at https://en.wikipedia.org/wiki/Friedmann–Lemaître–Robertson–Walker_metric (sometimes just called the Friedmann-Robertson-Walker metric or FRW). A black hole metric has a radial parameter where curvature gets larger the closer you are to the the black hole, and approaches zero the farther you get (the metric is 'asymptotically flat'), whereas the FLRW is completely uniform in the curvature and density of matter/energy throughout all of space at every moment of the cosmological time parameter.ÂPenrose himself refers to the fact that the flat and open versions of the FRW solution imply a spatially infinite universe on pages 323-324 of his book "The Emperor's New Mind":Firstly, if the age of the universe is finite, it can't expand spatially to infinity regardless of its rate of expansion.The FLRW metric for a flat or negatively curved universe does not describe a universe that "expands spatially to infinity", it is already infinite at *every* finite time interval after the Big Bang, and there is no size at T=0 because the singularity is more like the edge of spacetime than a part of the spacetime.
ÂSo if the universe is spatially infinite, this must have been its initial condition. Secondly, current theory is that the very very early universe was hugely hot, at a much higher temperature than at present. This implies, for me, that it was small, analogous to a highly compressed gas. IMO, it can't be small and hot, and also be spatially infinite.Presumably you can imagine an infinite plane covered with dots that are on average 1 meter apart, and a different infinite plane covered with dots that are on average 1 millimeter apart; this illustrates how the notion of particles having a higher or lower density doesn't depend on there being a finite number of them. And the bottom line is that an infinite space whose density changes with time is a mathematically allowable solution to the Einstein field equations, physicists trust math over personal gut feelings and intuitions.
ÂIf it's not spatially infinite, it can't be flat. As it contracts, if it forms a singularity with all its mass and energy concentrated in a tiny region, it will presumably form a BH.Not according to general relativity, no. The classic "Usenet Physics FAQ" at https://math.ucr.edu/home/baez/physics/index.html addresses this point specifically in the question and answer at https://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/universe.html where part of the answer is:
>Why did the universe not collapse and form a black hole at the beginning?
>Sometimes people find it hard to understand why the Big Bang is not a black hole. After all, the density of matter in the first fraction of a second was much higher than that found in any star, and dense matter is supposed to curve spacetime strongly. At sufficient density there must be matter contained within a region smaller than the Schwarzschild radius for its mass. Nevertheless, the Big Bang manages to avoid being trapped inside a black hole of its own making and paradoxically the space near the singularity is actually flat rather than curving tightly. How can this be?
>The short answer is that the Big Bang gets away with it because it is expanding rapidly near the beginning and the rate of expansion is slowing down. Space can be flat even when spacetime is not. Spacetime's curvature can come from the temporal parts of the spacetime metric which measures the deceleration of the expansion of the universe. So the total curvature of spacetime is related to the density of matter, but there is a contribution to curvature from the expansion as well as from any curvature of space. The Schwarzschild solution of the gravitational equations is static and demonstrates the limits placed on a static spherical body before it must collapse to a black hole. The Schwarzschild limit does not apply to rapidly expanding matter.ÂPlanck data allows for a positively and negatively geometry, but the dats for flatness is more persuasive. I believe is it so huge that we can't distinguish between positively curved and flat. It's likely approximately spherical in shape because the expansion is approximately uniform as evidenced by the near uniformity in outward expansion of the Cosmological Red Shift. AGÂIt's certainly possible it is positively curved but so large (much larger than the observable region) that it's indistinguishable from flatness given the precision of our current best measurements. But if you think you can conclude this *must* be the case a priori just given your verbal arguments (arguments which contradict what the GR equations say is a mathematically valid solution), no physicist is going to go along with that.
Jesse
On Sunday, February 9, 2025 at 2:22:29 PM UTC-7 Jesse Mazer wrote:On Sun, Feb 9, 2025 at 3:57 PM Alan Grayson <agrays...@gmail.com> wrote:On Sunday, February 9, 2025 at 10:08:36 AM UTC-7 Jesse Mazer wrote:On Sun, Feb 9, 2025 at 2:04 AM Alan Grayson <agrays...@gmail.com> wrote:On Saturday, February 8, 2025 at 3:26:33 PM UTC-7 Brent Meeker wrote:
On 2/8/2025 12:47 AM, Alan Grayson wrote:
I can't recall on which thread I made the argument, and Clark agreed, that if the universe has a finite age, it cannot be infinite in spatial extent. In response, Clark and Brent claimed it could've began as infinite. Isn't there a theorem, which might have been proven by Penrose, that the contracting universeOnly the observable universe, if I recall correctly.Applying the Penrose-Hawking Singularity Theorem, running the clock backward implies the universe doesn't converge to a point of zero volume, but to a BH, and that's the whole universe, not just the observable universe. AGThe Penrose-Hawking singularity theorems only implies an initial singularity, it doesn't say the universe was a black hole or that the whole universe (not just the observable part) must be finite--a black hole metric is different GR solution than the Friedmann–Lemaître–Robertson–Walker metric for an expanding universe at https://en.wikipedia.org/wiki/Friedmann–Lemaître–Robertson–Walker_metric (sometimes just called the Friedmann-Robertson-Walker metric or FRW). A black hole metric has a radial parameter where curvature gets larger the closer you are to the the black hole, and approaches zero the farther you get (the metric is 'asymptotically flat'), whereas the FLRW is completely uniform in the curvature and density of matter/energy throughout all of space at every moment of the cosmological time parameter.ÂPenrose himself refers to the fact that the flat and open versions of the FRW solution imply a spatially infinite universe on pages 323-324 of his book "The Emperor's New Mind":Firstly, if the age of the universe is finite, it can't expand spatially to infinity regardless of its rate of expansion.The FLRW metric for a flat or negatively curved universe does not describe a universe that "expands spatially to infinity", it is already infinite at *every* finite time interval after the Big Bang, and there is no size at T=0 because the singularity is more like the edge of spacetime than a part of the spacetime.That's my claim to some extent, that it must begin as infinite, if it has finite age and is NOW infinite in spatial extent. But beginning as infinite implies some problems which should be discussed. And maybe FLRW shouldn't assume it's flat. AG
ÂSo if the universe is spatially infinite, this must have been its initial condition. Secondly, current theory is that the very very early universe was hugely hot, at a much higher temperature than at present. This implies, for me, that it was small, analogous to a highly compressed gas. IMO, it can't be small and hot, and also be spatially infinite.Presumably you can imagine an infinite plane covered with dots that are on average 1 meter apart, and a different infinite plane covered with dots that are on average 1 millimeter apart; this illustrates how the notion of particles having a higher or lower density doesn't depend on there being a finite number of them. And the bottom line is that an infinite space whose density changes with time is a mathematically allowable solution to the Einstein field equations, physicists trust math over personal gut feelings and intuitions.Many, if not most of the major advances in physics have been the result of personal gut feelings and intuitions. I think it was Feynman who offered the insight that most advances in physics were based in guesses. Yes guesses. Shall I trust physicists such a Carroll who knows GR intimately and yet has evolved into a MW clown? AG
ÂIf it's not spatially infinite, it can't be flat. As it contracts, if it forms a singularity with all its mass and energy concentrated in a tiny region, it will presumably form a BH.Not according to general relativity, no. The classic "Usenet Physics FAQ" at https://math.ucr.edu/home/baez/physics/index.html addresses this point specifically in the question and answer at https://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/universe.html where part of the answer is:
>Why did the universe not collapse and form a black hole at the beginning?
>Sometimes people find it hard to understand why the Big Bang is not a black hole. After all, the density of matter in the first fraction of a second was much higher than that found in any star, and dense matter is supposed to curve spacetime strongly. At sufficient density there must be matter contained within a region smaller than the Schwarzschild radius for its mass. Nevertheless, the Big Bang manages to avoid being trapped inside a black hole of its own making and paradoxically the space near the singularity is actually flat rather than curving tightly. How can this be?
>The short answer is that the Big Bang gets away with it because it is expanding rapidly near the beginning and the rate of expansion is slowing down. Space can be flat even when spacetime is not. Spacetime's curvature can come from the temporal parts of the spacetime metric which measures the deceleration of the expansion of the universe. So the total curvature of spacetime is related to the density of matter, but there is a contribution to curvature from the expansion as well as from any curvature of space. The Schwarzschild solution of the gravitational equations is static and demonstrates the limits placed on a static spherical body before it must collapse to a black hole. The Schwarzschild limit does not apply to rapidly expanding matter.ÂPlanck data allows for a positively and negatively geometry, but the dats for flatness is more persuasive. I believe is it so huge that we can't distinguish between positively curved and flat. It's likely approximately spherical in shape because the expansion is approximately uniform as evidenced by the near uniformity in outward expansion of the Cosmological Red Shift. AGÂIt's certainly possible it is positively curved but so large (much larger than the observable region) that it's indistinguishable from flatness given the precision of our current best measurements. But if you think you can conclude this *must* be the case a priori just given your verbal arguments (arguments which contradict what the GR equations say is a mathematically valid solution), no physicist is going to go along with that.Did I ever say anything "must" be the case? I don't think a spherical universe, finite in spatial extend and expanding, contradicts GR equations. AGÂ
I suspect you are also doing the opposite of what Feynman recommends when you dismiss advocates of the MWI like Carroll as "clowns" -- you seem to dismiss it based on physical or philosophical intuitions that lead you to judge that the picture of a vast number of decoherent histories is absurd, and aren't just thinking in terms of criteria like mathematical elegance/simplicity which is why its advocates tend to favor it.ÂÂIf it's not spatially infinite, it can't be flat. As it contracts, if it forms a singularity with all its mass and energy concentrated in a tiny region, it will presumably form a BH.Not according to general relativity, no. The classic "Usenet Physics FAQ" at https://math.ucr.edu/home/baez/physics/index.html addresses this point specifically in the question and answer at https://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/universe.html where part of the answer is:
>Why did the universe not collapse and form a black hole at the beginning?
>Sometimes people find it hard to understand why the Big Bang is not a black hole. After all, the density of matter in the first fraction of a second was much higher than that found in any star, and dense matter is supposed to curve spacetime strongly. At sufficient density there must be matter contained within a region smaller than the Schwarzschild radius for its mass. Nevertheless, the Big Bang manages to avoid being trapped inside a black hole of its own making and paradoxically the space near the singularity is actually flat rather than curving tightly. How can this be?
>The short answer is that the Big Bang gets away with it because it is expanding rapidly near the beginning and the rate of expansion is slowing down. Space can be flat even when spacetime is not. Spacetime's curvature can come from the temporal parts of the spacetime metric which measures the deceleration of the expansion of the universe. So the total curvature of spacetime is related to the density of matter, but there is a contribution to curvature from the expansion as well as from any curvature of space. The Schwarzschild solution of the gravitational equations is static and demonstrates the limits placed on a static spherical body before it must collapse to a black hole. The Schwarzschild limit does not apply to rapidly expanding matter.ÂPlanck data allows for a positively and negatively geometry, but the dats for flatness is more persuasive. I believe is it so huge that we can't distinguish between positively curved and flat. It's likely approximately spherical in shape because the expansion is approximately uniform as evidenced by the near uniformity in outward expansion of the Cosmological Red Shift. AGÂIt's certainly possible it is positively curved but so large (much larger than the observable region) that it's indistinguishable from flatness given the precision of our current best measurements. But if you think you can conclude this *must* be the case a priori just given your verbal arguments (arguments which contradict what the GR equations say is a mathematically valid solution), no physicist is going to go along with that.Did I ever say anything "must" be the case? I don't think a spherical universe, finite in spatial extend and expanding, contradicts GR equations. AGÂWell, you said in the original post your view was that "if the universe has a finite age, it cannot be infinite in spatial extent" -- I would normally take "cannot be infinite" as synonymous with "must be finite", but maybe you didn't mean it that strongly, and were just expressing an intuition? In the post I first responded to it also seemed like you were trying to use the Hawking-Penrose theorems to show the finiteness of the universe, those theorems are supposed to apply to any spacetime satisfying the GR equations whatsoever, so if the theorems implied finiteness that would imply the universe "must" be finite in the context of GR (leaving aside the issue that GR will likely turn out to only be an approximation to a future theory of quantum gravity), but since Penrose considers infinite universes to be a viable possibility that presumably isn't the case.
Jesse
Jesse