D(f(x))...

[BH]

Dear all,

is it now possible to use the D-operator on functions?

I want to find an equation like:

y=f(x)*...+D(f(x),t,1)*...

Best regards

[Michael Schmidt]

Not yet, but you could do a numerical derivative manually using delay(), for example:

y = (f(x) - delay(f(x), 1))/(t - delay(t,1))

This is roughly: find a model f(x) who's derivative df(x)/dt models y

Michael