MemberExpression issue

[Dima Vidmich]

Hi,

I don't know is it a bug or I'm doing something wrong.

For for.bar and foo[bar]  I got the same AST

Shouldn't it be converted to Literal instead of Identifier in first case?

[Chris Toshok]

Arguably.  I think the shift parser/ast does something like this?

In esprima the differentiator for these cases is the .computed attribute on MemberExpressions.  it'll be true for the second, false for the first.

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