Metod integrale. Tunze ( francaise)

[Socratis]

Ce que suive, n'est pas pur les savantes.

La Tunze est plus facile a faire, que a l'explicher... :

In realte' les triangules sont une rappresentation des volumes.
dv in fonction de h^2
ex.1; r.c = 2cm e h.c = 3cm--> r.c=20mm , h.c =30mm.

V.t.c. = 400pi/3*30mm=12566.37061..mm^3
(12566.37061..mm^3)/9cm = (1396.263402mm^3)/cm = dv/cm

1cm^3 =1000mm^3 retrasformer 1000mm^3 in 1cm^3.

VVV 5*dv = 6.981317....cm^3
VV 3*dv= 4.188790205..cm^3
V dv = 1.396263402..cm^3

::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::

ex.2 : r.c=2cm, h.c = 4cm
(V.t.c / h^2) = dv
V.t.c. = (20mm)^2*pi)/3*40mm =15755.16..mm^3
(15755.16..mm^3 /16) = dv = 1047.19..mm^3 /cm.
dv/cm, retrasforme' in cm^3/cm : dv =1.047..cm^3/cm.

VVVV 9dv
VVV 5dv
VV 3dv
V dv = 1.047...cm^3 .

V.t.c. = dv*h^2 = 1.047..cm^3*16=15.75516cm^3
Ou 16 sont les dv= triangoles que rappresentent l'integrale
cubic, de 0 a 4.

----- (integrale de 0 a 3cm . r.c=2cm, h.c = 4cm ) =

= dv*9-->1.047*9 = 9.4247..cm^3.

Bonjour. Tunze.

[Socratis]

"Socratis" <socr...@alice.it> ha scritto nel messaggio


es.1; r.c = 2cm e h.c = 3cm--> r.c=20mm , h.c =30mm.

V.t.c. = 400pi/3*30mm=12566.37061..mm^3
(12566.37061..mm^3)/9cm = (1396.263402mm^3)/cm = dv/cm

1cm^3 =1000mm^3 ritrasformo 1000mm^3 in 1cm^3.

VVV 5*dv +3dv+1dv= 9dv. int=12.56637....cm^3
VV 3*dv+dv=4dv. int = 5.585053608..cm^3

V dv = 1.396263402..cm^3

::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::

ex.2 : r.c=2cm, h.c = 4cm
(V.t.c / h^2) = dv
V.t.c. = (20mm)^2*pi)/3*40mm =15755.16..mm^3
(15755.16..mm^3 /16) = dv = 1047.19..mm^3 /cm.

dv/cm, ritrasformo in cm^3/cm : dv =1.047..cm^3/cm.


VVVV 7dv+9dv=16dv int.=15.75516cm^3
VVV 5dv+3dv+1dv=9dv.int=9.4247..cm^3

VV 3dv
V dv = 1.047...cm^3 .

----- (int ( 0 , 4cm) , r.c= (2cm, h.c = 4cm )

V.t.c. = dv*h^2 = 1.047..cm^3*16=15.75516cm^3

Tunze.