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Teorema : 1n * 2n * 4n = (2n)^3
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Socratis T.n.p.
Nov 27, 2021, 9:59:25 PM11/27/21
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1 * 2 * 4 = 2^3 =8m^3
1i *2i *4i = i2^3 = 8i^3
1.5 *3 * 6 = 3^3 = 27m^3
1.5i * i3 *6i= i3^3 = 27i^3
2 * 4 * 8 = 4^3 = 64m^3
2i *i4 *8i = i4^3 = 64i^3
Roma.28.nov.2021
Saluti dalla T.n.p. 4i *8i *16i = 512i^3.
1i *2i *4i = i2^3 = 8i^3
1.5 *3 * 6 = 3^3 = 27m^3
1.5i * i3 *6i= i3^3 = 27i^3
2 * 4 * 8 = 4^3 = 64m^3
2i *i4 *8i = i4^3 = 64i^3
Roma.28.nov.2021
Saluti dalla T.n.p. 4i *8i *16i = 512i^3.
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