===>a^3+b^3+c^3 = (a+b+c)*(b^2+2d^2).
d =1) 4^3 +5^3 + 6*3==15 * (25 +2*(1^2) =1 *15 * 27== 405m^3
d =2) 4^3 +6^3 + 8^3==18 * (36 +2*(2^2) =1 *18 * 44== 792m^3
d =3) 4^3 +7^3+10^3== 21* (49 +2*(3^2) =1 *21 * 67 =1407m^3
d =4) 4^3 +8^3 +12^3 = 24* (64 +2*(4^2) =1 *24 * 96 =2304m^3
d =5) 4^3 +9^3 +14^3 = 27* (81 +2*(5^2) =1* 27 *131=3537m^3
0.2 *2 *2 = 2i *20i *20i = 400i^3 ==> For you 0.4m^3
Greetings from Socratis T.n.p. 2i * 4i * 8i = i4^3 =64i^3 =0.064m^3.
However you want to understand it..its value does. not change- :))
Rome. 20. Jan..2022.