Dave Squire's Explanation

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eldarion

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Jan 1, 2007, 3:26:20 AM1/1/07
to Energy Mover
All,

I ran across this page ( http://jnaudin.free.fr/meg/megdsqth.htm )
while looking through Naudin's MEG pages. What do you think of it?

I couldn't find the error right off the bat, but there must be one
because the silicon-iron MEG did not work, and this claims it should.

Thanks!

Eldarion

g trump

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Jan 1, 2007, 3:48:46 PM1/1/07
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Eldarion,
 
I wonder if this person, Dave Squires is still around. The posting was way back in 2000. I do like the thought of what he talked about, I mentioned that to Paul a few days ago, the exact same idea.
 
 
 
Trump. 
 
-------Original Message-------

g trump

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Jan 1, 2007, 3:53:23 PM1/1/07
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Eldarion,
 
Here is another one on the MEG,
 
http://jnaudin.free.fr/meg/meg.htm I did not read every word, but this seems to be a little more up to date.
 
 
Trump
 
-------Original Message-------
 
From: eldarion
Date: 1/1/2007 2:26:22 AM
Subject: Dave Squire's Explanation
 

MeggerMan

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Jan 3, 2007, 10:42:01 AM1/3/07
to Energy Mover
The explanation is true to a point, I myself found I could get a very
large flux to switch with a tiny amount of power.
I think that when you start to load the output coil, the flux will
refuse to switch.
There could be a trick where by you have to wait for the avalanche of
flux to start switching(change in electron spin orbit as the flux
direction changes), then catch it in mid cycle.

Regards
Rob

eldarion

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Jan 3, 2007, 1:23:57 PM1/3/07
to Energy Mover
Rob,

I would be interested in experimenting with just such a flux switching
mechanism.

How did you get the large flux to switch? MEG-type system?

Once again, timing may be critical here. Maybe let the flux change go
past the point of no return, then switch in the load?

Thanks,

Eldarion

MeggerMan

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Jan 4, 2007, 8:01:47 AM1/4/07
to Energy Mover
Yes using a Femm 4 simulation:
http://i100.photobucket.com/albums/m25/kingrs/megv1-2.jpg
Loads more pics in the album related to the MEG.
I think you need to switch in the load while the flux is switching.

Here is a thought, light travels at 299,792,458 meters/second.
If you had a thick piece of wire 299,792,458 meters long, a bulb, a
battery and a switch.
You turn on the switch for one second, does the light bulb light after
1 second then go off after 1 second of being on?
Also does the battery discharge the same power as consumed by the bulb
in one second?
But if that is the case then what if you removed the bulb before the
one second is up?
What ever way you look at this experiment there are some possible odd
outcomes.

Regards
Rob

Paul

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Jan 4, 2007, 10:25:42 AM1/4/07
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Hi,
There will always be exceptions, and not all things
operate according to
known physics. For example, there are standard
equations that apply to
magnetic cores in the case of inductors and
transformers, but those
equations do not always work as in the case of the MEG
due to PME.

I am not a big fan of paper work; i.e., mathematical
equations. Such
paper work attempts to compress complex situations
into a small area
(mathematical equation). The problem is nature is
vast even though it
is fundamental. Can you imagine trying to compress a 4
MB photo into
0.00004 MB, LOL? That's why I ***firmly*** believe
the future of
physics is in computer simulations, algorithms, etc.
For me, the
computer is my mathematical equation-- far more
powerful and complex.
Sure, you can use calculus and such in the computer
software, but the
computer is fast, precise, predictable, with a pretty
good memory. ;-)
The computer merely needs the aid of intelligence. A
computer can
simulate millions of objects and beyond.

What you described above could be an anomaly, but
classically speaking
light (so-called photons) travel *up to* c (299792458
m/s) and only in a
pure vacuum has it been observed to travel at or close
to c. Not that
it makes much difference to your example, but the
electric waves in bare
wire travel around 1/3 c, and closer to c in coaxial
cables due to less
inductance.

If you had a really long wire connected to a battery
and at the end a
bulb like you describe then what would happen is
during the initial
stage energy would go into the wires as inductance and
of course heat
due to resistance. That's why you often hear a loud
ping from telephone
power lines when the power company suddenly and
unexpectedly loses
power; i.e., there's still energy in the lines so it
rapidly collapses
generating a huge pulse that pings. Under desirable
conditions the
power company would slowly decrease the energy flow in
the lines, but
sometimes they have problems or perhaps a lightning
bolt strike blows a
main transformer. So during that 1 second you are
pumping energy into
the line. That energy will traverse down the line in
an electric pulse.
Furthermore, some of the energy will radiate out in to
space due to
radiation resistance in the line. If you remove the
bulb before that
pulse arrives then the pulse (actually there could be
two pulses, one in
each wire, if your battery is below ground) will
simply reflect back in
the opposite direction toward the battery, in which
case the battery
will absorb a certain amount and the rest of the pulse
will reflect back
again until the battery, electrical and radiation
resistance (etc)
dissipate the energy pulse.

Regards,
Paul Lowrance


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