How to decode JSON object with more than 8 fields?

[Petr Huřťák]

For 8 fields or less I can do

import Json.Decode as Decode exposing ((:=))

collectionDecoder : Decode.Decoder (List Test)

collectionDecoder =

    Decode.list

        (Decode.object8 Test

            ("id" := Decode.int)

            ...

        )

How to decode JSON object with more than 8 fields?

[Peter Damoc]

use (|:) from Json.Decode.Extra
http://package.elm-lang.org/packages/elm-community/json-extra/1.0.0/Json-Decode-Extra#|:

--
You received this message because you are subscribed to the Google Groups "Elm Discuss" group.
To unsubscribe from this group and stop receiving emails from it, send an email to elm-discuss...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

--

There is NO FATE, we are the creators.
blog: http://damoc.ro/

[Aditya Vishwakarma]

If you wish to know how to do it, then take a look at this : https://github.com/adityav/elm-reddit-listing/blob/master/src/Decoders.elm#L14

Once you understand how it is done, you can use http://package.elm-lang.org/packages/NoRedInk/elm-decode-pipeline/1.1.2 package. 

[Pablo Parga]

This is a great tool to encode/decode : http://noredink.github.io/json-to-elm/