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2,dereceden denklem
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bekir yeşilkaya
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Feb 10, 2008, 2:48:02 PM
2/10/08
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xkare-2x+5-a=0 denklemının kökleri x1 ve x2 dir.
x1(bir yanı altta)=-2x2(2 yanı altta) olduguna göre a kaçtır?
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Dr.Yasemin
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Feb 10, 2008, 2:51:30 PM
2/10/08
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x1 +x2 = 2
-2x2 +x2 = 2
-x2= 2
x2= -2
x1= 4
5-a = x1 .x2
5-a= 4.-2
5-a=-8
a=13
A. A.
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