I'm not clear on how to write Q1 and Q0 as a function of revenue...
Can anyone clear this up?
Kevin
On Feb 16, 11:13 am, Carla Nunes <
ccrnu...@gmail.com> wrote:
> Hi Robert,
>
> I used the formula:
>
> ∆Q/Q = Ep * ∆P/P, where ∆Q = Q1 - Q0, and ∆P = P1 - P0.
>
> Since we don't have Q1 or Q0, we write those as a function of revenue (R0),
> which will get cancelled out in the Ep formula.
>
> If you want, I can send you my calculations.
>
> Also, I don't think we need to come up w/ a specific price for this answer.
> We only need to say whether they should raise the price, lower it, or keep
> the same, and why.
>
> Carla
> On Wed, Feb 16, 2011 at 10:07 AM, Robert Binkley
> <
Robert.Bink...@xilinx.com>wrote:
>
>
>
>
>
>
>
> > For the Cable Car problem, calculating the Elasticity can also be done
> > this way:
>
> > %∆Q = Ep * %∆P where %∆Q = %∆R - %∆P
>
> > This gives the answer Ep = -.657
>
> > I am not sure why this Ep is different than yours.
>
> > The hard part I am struggling with is how to pick the optimal price, we
> > know it should be higher than 5 dollars. A cost figure is provided so how
> > do we maximize profit.
>
> > Can we assume cost is fixed so all we need to do is set the price to
> > maximize revenue at Ep=-1? Do we need to create a demand function?
>
> > -rob
>
> > *From:*
econ_401_w...@googlegroups.com [mailto:
> >
econ_401_w...@googlegroups.com] *On Behalf Of *alex smirnov
> > *Sent:* Tuesday, February 15, 2011 9:08 PM
>
> > *To:*
econ_401_w...@googlegroups.com
> > *Subject:* Re: Readings for this week...
>
> > alright, i got the same thing Carla got.
>
> > P0 = $5/1.67 = $3
>
> > Then simply express both Q1 and Q0 in terms of either R1 or R0 (R1 =
> > 1.27R0) and put that into the Ep equation
>
> > Ep = ((Q1-Q0)/(P1-P0)*(P1/Q1))
>
> > now on to OMIS 355 homework...
>
> > On Tue, Feb 15, 2011 at 6:16 PM, alex smirnov <
alex.smir...@gmail.com>
> > wrote:
>
> > I got the same for DW. and also said that it is within range, but hard to
> > tell with 4 observations
>
> > how did you guys calculate the Elasticity for the cable car problem?
>
> > this is confusing. One part talks about a 67% increase (to $5) which means
> > that fares went from $3 to $5
>
> > Another part says that "cable car fares more than doubled"
>
> > which is it 67% or doubled?
>
> > And I can't figure out how I get the info on the change in demand
>
> > On Tue, Feb 15, 2011 at 5:15 PM, Carla Nunes <
ccrnu...@gmail.com> wrote:
>
> > I don't know if I understand what he means. I did the DW test and mine
> > shows as 2.38, not an ideal number but, it is still within the 1.5 and 2.5
> > range, so I said it's not serially correlated.
>
> > On Tue, Feb 15, 2011 at 5:10 PM, Adi Aloni <
aloni....@gmail.com> wrote:
>
> > Hi guys,
>
> > I’m posting my question and the professor’s answer to it. Now tell me what
> > tests I should include in my answers….
>
> > Q: In the logistic model, since we have so few observations, do we still
> > calculate DW and check residuals and so on?
> > In a broader context, is there any case in which we reject the linear
> > regression results in this model?
>
> > A: Thanks Adi. I forgot to mention in class that one expects highly
> > correlated residuals in a model like this. The only question is does it fit.
> > If it fits poorly the model will do poorly
>
> > Adi.
>
> > *From:*
econ_401_w...@googlegroups.com [mailto:
> >
econ_401_w...@googlegroups.com] *On Behalf Of *Carla Nunes
>
> > *Sent:* Tuesday, February 15, 2011 3:38 PM
> > *To:*
econ_401_w...@googlegroups.com
> > *Subject:* Re: Readings for this week...
>
> > This is what I got for the cable ride question:
>
> > Elasticity = -0.887 (inelastic), so they should raise prices.
>
> > Let me know if you have the same (or not) :)
>
> > On Tue, Feb 15, 2011 at 3:14 PM, Carla Nunes <
ccrnu...@gmail.com> wrote:
>
> > Adi, Alex, which other regressions you're talking about?
>
> > On Tue, Feb 15, 2011 at 3:04 PM, alex smirnov <
alex.smir...@gmail.com>
> > wrote:
>
> > i'm not sure........i just remember that Heineke mentioned that the TA went
> > easy on the grading, but in the future he wants that stuff
>
> > perhaps the residual tests don't make sense.......but T-critical and
> > F-critical values are still valid
>
> > On Tue, Feb 15, 2011 at 2:46 PM, Adi Aloni <
aloni....@gmail.com> wrote:
>
> > Alex – are you sure we have to go through all the linear regression tests
> > in this model? There are so few observations, it doesn’t make sense…
>
> > *From:*
econ_401_w...@googlegroups.com [mailto:
> >
econ_401_w...@googlegroups.com] *On Behalf Of *jonathan car
> > *Sent:* Tuesday, February 15, 2011 2:38 PM
>
> > *To:*
econ_401_w...@googlegroups.com
> > *Subject:* Re: Readings for this week...
>
> > Carla is once again correct. My sF is calculated wrong. It should be
> > s(5) = S(5) – S(4), instead of s(5) - S(5) - s(4)
>
> > Thank you Carla
>
> > Jonathan
> > ------------------------------
>
> > *From:* Carla Nunes <
ccrnu...@gmail.com>
> > *To:*
econ_401_w...@googlegroups.com
> > *Sent:* Tue, February 15, 2011 2:07:47 PM
> > *Subject:* Re: Readings for this week...
>
> > s(5) = S(5) – S(4), so for both S(5) and S(4), i use the model. That will
> > give us the sales for the quarter alone according to the model.
>
> > In my case, I get S(5) = 1513.13, S(4) = 668.41, which gives me s(5) =
> > 844.72
>
> > With that, you compare w/ the given sales for quarter 5, which is 836.
>
> > That's what I think it should be done, but again, never 100% sure.
>
> > On Tue, Feb 15, 2011 at 2:00 PM, Adi Aloni <
aloni....@gmail.com> wrote:
>
> > OK… here’s where it gets sticky…
>
> > What number do we use for calculating the forecasted stand alone Q5 sales?
> > If we use the actual cumulative sales data up to the 4th qtr, I got a
> > forecast of 882 with 5.5% error. However, I’m not sure we should use the
> > actual number, because in part c we calculate all 5 quarters based on the
> > forecast.
>
> > What do you think? Is it worth emailing the professor/TA?
>
> > *From:*
econ_401_w...@googlegroups.com [mailto:
> >
econ_401_w...@googlegroups.com] *On Behalf Of *Carla Nunes
> > *Sent:* Tuesday, February 15, 2011 1:56 PM
>
> > *To:*
econ_401_w...@googlegroups.com
> > *Subject:* Re: Readings for this week...
>
> > Yes, that's what I did. Not sure if it's correct though, so I sent an
> > email to the TA to confirm. Still waiting for her response.
>
> > For part a, I now got: 844.72. error = 1.043%
>
> > Let me know if this is what you got.
>
> > Carla
>
> > On Tue, Feb 15, 2011 at 1:50 PM, Adi Aloni <
aloni....@gmail.com> wrote:
>
> > How did you calculate % error for part d? we don’t have actual numbers…
>
> > Is it compared to the 75% prediction?
>
> > *From:*
econ_401_w...@googlegroups.com [mailto:
> >
econ_401_w...@googlegroups.com] *On Behalf Of *Carla Nunes
> > *Sent:* Tuesday, February 15, 2011 1:45 PM
>
> > *To:*
econ_401_w...@googlegroups.com
> > *Subject:* Re: Readings for this week...
>
> > Good point, Adi. I did the calculation for the cumulative values, not the
> > quarter itself. Let me update my sheet.
>
> > On Tue, Feb 15, 2011 at 1:39 PM, Adi Aloni <
aloni....@gmail.com> wrote:
>
> > Hi,
>
> > Notice that 1513 is the cumulative sales up to the 5th quarter. You have
> > to subtract the cumulative sales up to the 4th quarter to get the numbers
> > for the 5th quarter alone.
>
> > I think we’re supposed to calculate the model error according to the 5thquarter alone.
>
> > Adi.
>
> > *From:*
econ_401_w...@googlegroups.com [mailto:
> >
econ_401_w...@googlegroups.com] *On Behalf Of *Carla Nunes
> > *Sent:* Tuesday, February 15, 2011 12:56 PM
>
> > *To:*
econ_401_w...@googlegroups.com
>
> > *Subject:* Re: Readings for this week...
>
> > Guys, here are my answers for Thompson:
>
> > a) regression model w/ coefficients
>
> > Intercept
>
> > -8.263946887
>
> > t
>
> > 0.825933324
>
> > b) sales in 5th quarter = 1513.13; %error = 3.145%
>
> > c) based on graph, model predicts well
>
> > d) model's prediction = 83.85%, so %error = 11.8%
>
> > Let me know if you guys got the same.
>
> > See ya,
>
> > Carla
>
> > On Tue, Feb 15, 2011 at 11:16 AM, Carla Nunes <
ccrnu...@gmail.com> wrote:
>
> > Ok, good, Alex. At least we got same numbers for the regression. Once I'm
> > done w/ the other calculations, I'll post them here to check again.
>
> > On Tue, Feb 15, 2011 at 11:10 AM, alex smirnov <
alex.smir...@gmail.com>
> > wrote:
>
> > Carla, my numbers are the same as yours
>
> > I wouldn't read too much into Jonathan's answers as they were done before
> > yesterday's lecture
>
> > btw, I hope y'all don't forget to get the critical values for both F and T
> > (excel functions) , as well as do the 3 residual tests (Durban Watson,
> > normalcy, and one other one I can't remember)
>
> > On Tue, Feb 15, 2011 at 10:31 AM, Spencer Hsu <
sphs...@gmail.com> wrote:
>
> > It seems he removed it based on the very high p values.
>
> > On Tue, Feb 15, 2011 at 10:21 AM, Carla Nunes <
ccrnu...@gmail.com> wrote:
>
> > No, I didn't get the same as Jonathan. In fact, I'm not sure why he
> > decided to remove the intercept, and why the two regressions.
>
> > On Tue, Feb 15, 2011 at 10:19 AM, Spencer <
sphs...@gmail.com> wrote:
>
> > So is jonathan's then?
>
> > Sent from my iPhone
>
> > On Feb 15, 2011, at 10:08 AM, Carla Nunes <
ccrnu...@gmail.com> wrote:
>
> > Did you guys get this:
>
> > Intercept
>
> > -8.263946887
>
> > t
>
> > 0.825933324
>
> > so, ln (S/(m-S) = a + bt = -8.26 + 0.826 t
>
> > Please let me know! Thx,
>
> > Carla
>
> > On Tue, Feb 15, 2011 at 9:56 AM, Gabriel Bowers <
gabrielbow...@gmail.com>
> > wrote:
>
> > ln(s/m-s) shows a linear relationship with t. Therefore, you can fit
> > 'a+bt' from this relationship.
>
> > On 2/15/11, Carla Nunes <
ccrnu...@gmail.com> wrote:
> > > Hi guys,
>
> > > Quick question on how to tackle this... we basically run a regression on
> > the
> > > column that will have the calculated ln (St / m-St). This column will be
> > > our LRS variable, and t will be our RHS variable. Correct?
>
> > > Do we need to run a different regression
>
> ...
>
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