EasyRTC connection issues on ReLogin

[Abhishek Sharma]

I am using EasyRTC with Nodewebkit and SailsJS.

1. First time when user logs in, I call EasyRTC server setup in my node app which returns EasyRTC id and occupants.
2. When user logs out, I am calling disconnect function which closes websocket connection.
3. If user tries to login again, Error thrown was : Develop Error, Attempt to connect when already connected to socket server.
   Above message was fixed by adding additional checks in if condition in this.connect method, i.e.
   
   if (self.webSocket && self.webSocket != undefined && self.webSocket != null) {

                    console.error("Developer error: attempt to connect when already connected to socket server");
                    return;

   }
   
    Now I don't get above error but connection is not getting established with server, i.e. I am not getting occupants and on adding console in server code, it was not showing any messages indicating that call was not made to server.
   If I reload app, it works but on relogin it does not.
   
   

Could you please help me in fixing issue or Let me know If I have made any mistakes?  

[Eric Davies]

Problem confirmed on the beta branch. I'll look into it sometime in the next few days.

[Arun Aravind]

Hi Eric,

I am also facing developer error issue can you please help its very very urgent

Thanks

Arun

[Eric Davies]

I've just tried disconnecting and reconnecting using the demo_audio_video demo on the beta branch (since that is where bugfixes go first). It seems to work fine. The only caveat I can think of is that you may need a short interval before connecting after a disconnect.

If you are having problems, please submit some code that demonstrates the problem. My time is limited, so something I can unzip into my demos or static folder and simply run is mandatory.

[Arun Aravind]

Thanks Eric,

we have developed the app using demo video audio . Already the app is in live.Is there any way to share the code with you prtivaely .

Arun

[Arun Aravind]

Hi ERIC,

below is the connection code that we have using in our APP please tell if anything went wrong.We are stuck with this issue ..

function connect_customer(nam) {

easyrtc.setSocketUrl(":8080");

var localFilter = easyrtc.buildLocalSdpFilter( {

        audioRecvBitrate:20, videoRecvBitrate:15

    });

    var remoteFilter = easyrtc.buildRemoteSdpFilter({

        audioSendBitrate: 20, videoSendBitrate:30

    });

    easyrtc.setSdpFilters(localFilter, remoteFilter);

easyrtc.setUsername(nam);

    easyrtc.setAcceptChecker(function(easyrtcid, callback) {

        document.getElementById('acceptCallBox').style.display = "block";

        callerPending = easyrtcid;

        if( easyrtc.getConnectionCount() > 0 ) {

            document.getElementById('acceptCallLabel').innerHTML = "Drop current call and accept new from " + easyrtc.idToName(easyrtcid) + " ?";

        }

        else {

            document.getElementById('acceptCallLabel').innerHTML = "Accept incoming call from " + easyrtc.idToName(easyrtcid) + " ?";

        }

        var acceptTheCall = function(wasAccepted) {

            document.getElementById('acceptCallBox').style.display = "none";

            if( wasAccepted ) {

                easyrtc.hangupAll();

            }

            callback(wasAccepted);

            callerPending = null;

        };

        document.getElementById("callAcceptButton").onclick = function() {

      

        //responsefn(true);

            acceptTheCall(true);

        };

        document.getElementById("callRejectButton").onclick =function() {

            acceptTheCall(false);

        };

        

        //responsefn(true);

    });

//file share

easyrtc.enableDataChannels(true);

//file share

easyrtc.setPeerListener(addToConversation);  

 

  if(vi_stat==2){

easyrtc.enableVideo(false);

}

if(au_stat==2){

   easyrtc.enableAudio(false);

}

    easyrtc.setRoomOccupantListener(convertListToButtons);

//file share

easyrtc.setDataChannelOpenListener(function(easyrtcid, usesPeer) {

        var obj = document.getElementById(buildDragNDropName(easyrtcid));

        if (!obj) {

            console.log("no such object ");

        }

        jQuery(obj).addClass("connected");

        jQuery(obj).removeClass("notConnected");

    });

    easyrtc.setDataChannelCloseListener(function(easyrtcid) {

        jQuery(buildDragNDropName(easyrtcid)).addClass("notConnected");

        jQuery(buildDragNDropName(easyrtcid)).removeClass("connected");

    });

    easyrtc.connect("easyrtc.audioVideo", loginSuccess, loginFailure);

easyrtc.easyApp("easyrtc.audioVideo", "selfVideo", ["callerVideo"], loginSuccess, loginFailure);

}

Thanks

[Eric Davies]

I can't be certain of what your error is because you didn't send me the corresponding HTML.

However, I think your problem is in your last two lines of the javascript. You are calling easyrtc.connect as well as easyrtc.easyApp. easyrtc.easyApp already calls easyrtc.connect; the whole point of easyrtc.easyApp was to package together the common stuff needed by simple applications [getting the local media, connecting, assigning media streams to video objects, handling disconnections]. Get rid of your call to easyrtc.connect. When you need to reconnect, simply call easyrtc.easyApp again. 

You can find this demonstrated in the files contained in this gist  https://gist.github.com/EricDavies/908ca6451dbd6a26d93e