> SDF: The SDF is basically a density measure (mm3) of water diffusing along different fiber directions in a voxel. Does this mean that if I looked at one voxel after QSDR reconstruction, I would see multiple density values in mm3 units per voxel, for each fiber direction?
Not exactly. Currently the SDF is normalized in a way that makes a
free water diffusion voxel has SDF=1 at all directions regardless of
the voxel size.
> Does the same apply to QA, that we would get a QA value for every fiber orientation in the voxel?
QA is measured after removing the isotropic component from the SDF.
It only has the anisotropic component.
>
> Connectometry: Translating this to the local connectome, is every element in the row vector corresponding to the local connectome of one individual is the SDF value along a specific fiber direction?
Yes.
> My biggest confusion is with the line that says "sample SDFs at local fiber direction from common atlas". Ultimately, what is each element in the row vector of the local connectome matrix in terms of one subject? Are there specific units? Understanding this would help us greatly in understanding how to interpret the results of the connectometry analysis.
Each element is the anisotropic SDF value of a subject sampled at one
fiber orientation. Here the fiber orientation is defined by the atlas,
not the SDF itself.
The value is a spin density measurement. In MRI, spin density has an
arbitrary unit, and it can only be scaled with respect to a reference.
Here the SDF is scaled in a way that free water SDF has value equals
one at all directions.
>
> I apologize if these questions are too basic, or if there is a simplified explanation somewhere that I have missed. Please feel free to direct me toward any simplified material that I can look at to better understand these metrics.have to e
No problem at all. This is not a basic question, and I often have to
explain several times in the DSI Studio workshop.
If there is still anything unclear, I will be more than happy to help
you clarify.
>
> Thank you so much for your time and patience, and of course kudos on developing a great tool!
My pleasure.
Frank
>
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