How to use inspectdb to generate a model for a table owned by a specific schema.

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Nemani Srinivas Murthy

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Sep 9, 2021, 10:10:08 AMSep 9
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Hi, I'm looking for a solution for generating the model.py file for a table which is owned by a specific schema <schema>.<table>, I tried the below option but no luck.

python manage.py inspectdb --database= <DB_NAME> <SCHEMA.TABLE_NAME>


carlos

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Sep 9, 2021, 10:13:18 AMSep 9
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On Thu, Sep 9, 2021 at 8:09 AM Nemani Srinivas Murthy <mr.n...@gmail.com> wrote:
Hi, I'm looking for a solution for generating the model.py file for a table which is owned by a specific schema <schema>.<table>, I tried the below option but no luck.

python manage.py inspectdb --database= <DB_NAME> <SCHEMA.TABLE_NAME>


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Carlos Rocha

Hello Singh

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Sep 10, 2021, 12:50:19 AMSep 10
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I am intermediate django developer, I want to give a try to your questions.
Simply use this command 
python manage.py inspectdb [ TABLE_NAME ]
If you use this command without table name it inspect all tables of database



On Thu, 9 Sep 2021, 19:39 Nemani Srinivas Murthy, <mr.n...@gmail.com> wrote:
Hi, I'm looking for a solution for generating the model.py file for a table which is owned by a specific schema <schema>.<table>, I tried the below option but no luck.

python manage.py inspectdb --database= <DB_NAME> <SCHEMA.TABLE_NAME>


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