Django 1.7, KeyError: u'manager' error

[Taenyon Kim]

Example

class ModelA(models.Model):

    fielda = models.CharField(max_length=10)

class ModelB(models.Model):

    modela = models.ForeignKey(ModelA)

    fieldb = models.CharField(max_length=10)

When I query like "modela_instance.modelb_set()", then I will get KeyError: u'manager' as shown below:

How can I solve this problem?

[Sanjay Bhangar]

On Fri, Oct 17, 2014 at 2:53 PM, Taenyon Kim <xos...@gmail.com> wrote:

Example

class ModelA(models.Model):

    fielda = models.CharField(max_length=10)

class ModelB(models.Model):

    modela = models.ForeignKey(ModelA)

    fieldb = models.CharField(max_length=10)

When I query like "modela_instance.modelb_set()", then I will get KeyError: u'manager' as shown below:

AFAIK, you want something like "modela_instance.modelb_set.all()" - just modela_instance.modelb_set() is the manager instance that you call call methods on (like 'all', 'filter', etc.), but calling the manager directly doesn't quite work, as you found out :)

All the best,

Sanjay