if >, if >= in templates?

[Steven Armstrong]

Hi

I've got the following in my template:

{% if reference_set.count %}
<ul>
{% for reference in reference_set.all|slice:":5" %}
<li><a href="{{ reference.website }}">{{ reference.name }}</a></li>
{% endfor %}
</ul>
{% endif %}

If there are more then 5 references I'ld like to show a 'more' link that
leads to a list of all references.

Something like (pseudocode):
{% if reference_set.count > 5 %}
<a href="/path/to/references">more</a>
{% endif %}

Anybody know how to do that?
Or am I missing something obvious?

[Don Arbow]

On Jun 25, 2006, at 1:13 PM, Steven Armstrong wrote:

If there are more then 5 references I'ld like to show a 'more' link that 

leads to a list of all references.

Something like (pseudocode):

{% if reference_set.count > 5 %}

<a href="/path/to/references">more</a>

{% endif %}

Anybody know how to do that?

Or am I missing something obvious?

Not sure if it works, but off the top of my head, what I would try is this:

{% if reference_set.all|slice:"5:" %}

should return true if the slice produces anything past the 5th element.

Don

[Ivan Sagalaev]

Don Arbow wrote:
> Not sure if it works, but off the top of my head, what I would try is this:
>
> {% if reference_set.all|slice:"5:" %}

Not exactly this. Here a DB (Postgres at least) will complain that it
can't set OFFSET without LIMIT. This would work:

{% if reference_set.all|slice:"5:6" %}

[Steven Armstrong]

Using sqlite, django also complained with AssertionError 'offset'
is not allowed without 'limit'.

Ivan's variation does the trick.

Thanks to both of you :)

cheers
Steven