Hi,
BTW it is flask app question.
dir structure
service
config/__init__.py
config/config.py
src/app.py
src/__init__.py
Running the flask app by writing command python src/app.py
Question: I want to access config parameter in flask app from config module of config package how can do that.
solutions I tried write sys.path.append(''../") to my src/__init__.py file but its not working please help me write this right way.
seems src/__init__.py is not being called.
I don't want to change my dir structure and I don't want to write sys.path.append(''../") in my app.py file,
Thanks in advance