Please explain "TypeError: handle_404() got an unexpected keyword argument 'exception'"

[Chris Seberino]

I'm trying to get a 404 page to show instead of a 500 error when Django app sees a nonexistent URL.

I'm still getting 500 errors with this clue in logs but I don't know what it means....

Please explain "TypeError: handle_404() got an unexpected keyword argument 'exception'"

(The nonexistent URL I tried was /aaa.)

Internal Server Error: /aaa

Traceback (most recent call last):

  File "/usr/local/lib/python3.5/dist-packages/django/core/handlers/exception.py", line 35, in inner

    response = get_response(request)

  File "/usr/local/lib/python3.5/dist-packages/django/core/handlers/base.py", line 113, in _get_response

    resolver_match = resolver.resolve(request.path_info)

  File "/usr/local/lib/python3.5/dist-packages/django/urls/resolvers.py", line 523, in resolve

    raise Resolver404({'tried': tried, 'path': new_path})

django.urls.exceptions.Resolver404: {'path': 'aaa', 'tried': [[<URLPattern '^$'>], [<URLPattern '^main/handle_404/$'>],

 [<URLPattern '^main/main/$'>], [<URLPattern '^explorer/search/$'>]]}

During handling of the above exception, another exception occurred:

Traceback (most recent call last):

  File "/usr/local/lib/python3.5/dist-packages/django/core/handlers/exception.py", line 99, in get_exception_response

    response = callback(request, **dict(param_dict, exception=exception))

TypeError: handle_404() got an unexpected keyword argument 'exception'

[Matemática A3K]

On Mon, Dec 11, 2017 at 10:23 PM, Chris Seberino <cseb...@gmail.com> wrote:

I'm trying to get a 404 page to show instead of a 500 error when Django app sees a nonexistent URL.

I'm still getting 500 errors with this clue in logs but I don't know what it means....

Please explain "TypeError: handle_404() got an unexpected keyword argument 'exception'"

It means literally that "handle_404() got an unexpected keyword argument 'exception'", how are you calling handle_404()?

 

(The nonexistent URL I tried was /aaa.)

Internal Server Error: /aaa

Traceback (most recent call last):

  File "/usr/local/lib/python3.5/dist-packages/django/core/handlers/exception.py", line 35, in inner

    response = get_response(request)

  File "/usr/local/lib/python3.5/dist-packages/django/core/handlers/base.py", line 113, in _get_response

    resolver_match = resolver.resolve(request.path_info)

  File "/usr/local/lib/python3.5/dist-packages/django/urls/resolvers.py", line 523, in resolve

    raise Resolver404({'tried': tried, 'path': new_path})

django.urls.exceptions.Resolver404: {'path': 'aaa', 'tried': [[<URLPattern '^$'>], [<URLPattern '^main/handle_404/$'>],

 [<URLPattern '^main/main/$'>], [<URLPattern '^explorer/search/$'>]]}

During handling of the above exception, another exception occurred:

Traceback (most recent call last):

  File "/usr/local/lib/python3.5/dist-packages/django/core/handlers/exception.py", line 99, in get_exception_response

    response = callback(request, **dict(param_dict, exception=exception))

TypeError: handle_404() got an unexpected keyword argument 'exception'

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[Chris Seberino]

Please explain "TypeError: handle_404() got an unexpected keyword argument 'exception'"

It means literally that "handle_404() got an unexpected keyword argument 'exception'", how are you calling handle_404()?

Thanks for your help.  In my urls.py I have this...

django.conf.urls.handler404 = "main.controllers.controllers.handle_404"

I believe that invokes the handle_404 function in the main/controllers/controllers.py file?

cs 

[Daniel Roseman]

And what does your handle_404 function look like? As the error says, it needs to accept an "exception" keyword argument.

Note also that overriding the 404 handler is a very specialized thing to do and is almost always not required. Why are you doing this?

--

DR.

[Chris Seberino]

And what does your handle_404 function look like? As the error says, it needs to accept an "exception" keyword argument.

Note also that overriding the 404 handler is a very specialized thing to do and is almost always not required. Why are you doing this?

Here it is..... The date is just to provide the current date at bottom for the copyright footer.  Are you saying views like this

are rare?

 def handle_404(request):

        """

        Handles 404 errors.

        """

        year = datetime.date.today().year

        return django.shortcuts.render(request,

                                       "handle_404.html",

                                       {"year" : year})

[Dylan Reinhold]

Your handle_404(request): needs to accept request, exception and template.

But if what you want this for is the current Year.

Just create a 404 template file in your template root named 404.html.

In the template use
{% now 'Y' %}

To get the current year.

The just let the default django 404 error process pick it up that as it's the default template to use for 404..

Make sure you have DEBUG=False for your testing.

Dylan

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