How to store a bank account number generated into a model field

[Dennis Alabi]

I tried but i don't seem to be getting it, please help

Views.py

from django.contrib import messages

from django.contrib.auth.decorators import login_required

from django.http import Http404

from django.shortcuts import render, redirect

from .forms import DepositForm, WithdrawalForm

from users.models import Profile

import random

from . import models

def random_gen():

# return a 10 digit random number

return int(random.uniform(1000000000, 9999999999))

def index(request):

try:

curr_user = Profile.objects.get(user=request.user) # getting details of current user

except:

# if no details exist (new user), create new details

curr_user = Profile()

curr_user.account_number = random_gen() # random account number for every new user

curr_user.balance = 0

curr_user.user = request.user

curr_user.save()

return render(request, "users/profile.html", {"curr_user": curr_user})

models.py

from django.db import models

from django.contrib.auth.models import User

from PIL import Image

class Profile(models.Model):

user = models.OneToOneField(User, on_delete=models.CASCADE)

image = models.ImageField(default='default.jpg', upload_to='profile_pics')

account_number = models.IntegerField(blank=False,null=False)

balance = models.IntegerField(blank=False,null=False)

def __str__(self):

return f'{self.user.username} Profile'

def save(self, *args, **kwargs):

super(Profile, self).save(*args, **kwargs)

img = Image.open(self.image.path)

if img.height > 300 or img.width > 300:

output_size = (150, 150)

img.thumbnail(output_size)

img.save(self.image.path)

[Ying Yu]

You could try the CharField to store the account number. Also, it is better to store the balance as FloatField

[Simon A]

I think the except block won't trigger since if the code Profile.objects.get(user=request.user) does not get any results, it will return a null result, not throw exception.

instead of exception handling, just check if the return value is null or not