Django URL pattern - template tags

[Petey]

 Hey

I've made a view which should generate url in form like this (example.com/type/id/slug : example.com/news/1/lorem-ipsum/)

To generate links I use:
<a href="/{{ n.type }}/{{ n.id}}/{{ n.slug }}">{{ n.title|safe}}</a>
It isn't the correct form for that as far as I know.

Could someone explain me how to use {% url %} tag in this situation? I dont quite understand this and I can't manage it to work :)

http://pastebin.com/mVU0iFXt

[Petey]

Problem solved.
I was too tired to find my mistake earlier ;)

[Tomas Neme]

I'll still answer this just in case. You should have the following in
your urls.py:

urlpatterns += (......,
url(r'(P<type>)\w+/(P<id>)\d+/(P<slug>)\[w-]+/', your_view,
name='yoururlname'), ....)

and then you can have in your template

<a href="{% url yoururlname type=n.type id=n.id slug=n.slug %}">{{
n.title }}</a>

I hope I didn't make any mistakes.

tomas

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[Piotr S]

All correct :)

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