How do detect if template is being viewed on mobile device?

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Django2021

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Mar 16, 2022, 4:28:38 PM3/16/22
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With Django how is it possible to detect
* if template is being viewed on mobile device?
and/or
* if template is being viewed in portrait or landscape mode?

Any suggestions appreciated.


Antonis Christofides

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Mar 16, 2022, 4:34:09 PM3/16/22
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Hello,

there are many ways to approach this problem, so it would be best to explain what you are trying to achieve.

Regards,

Antonis

Antonis Christofides
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Kasper Laudrup

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Mar 16, 2022, 4:34:19 PM3/16/22
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https://www.w3.org/TR/css3-mediaqueries/

Kind regards,

Kasper Laudrup
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Django2021

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Mar 16, 2022, 4:42:39 PM3/16/22
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> There are many ways to approach this problem, so it would be best to explain what you are trying to achieve.

Inside of a Django function or template we need to know if to display
a landscape or portrait of a form - based on knowing if the viewer is
using a mobile or not.

Django2021

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Mar 16, 2022, 4:45:01 PM3/16/22
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If only https://www.w3.org/TR/css3-mediaqueries/  had some practical examples in Python or Django, it could be useful.

Antonis Christofides

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Mar 17, 2022, 3:11:10 AM3/17/22
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Inside of a Django function or template we need to know if to display
a landscape or portrait of a form - based on knowing if the viewer is
using a mobile or not.

Your requirement to know whether you are using "landscape or portrait" is unusual. Normally we are only interested in knowing the width of the screen. If the screen is wide enough, we show the wide version, without caring about what the height of the screen is (it could be a large screen in portrait, for example).

In any case, I think you can solve it with CSS (even if you really want to take the height of the screen into account). This problem has nothing to with Python and Django, it's merely a HTML+CSS issue. If you don't want to learn much CSS, using a CSS framework like Bootstrap can help.

Regards,

Antonis

Antonis Christofides



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Kayode Oladipo

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Mar 21, 2022, 7:01:31 AM3/21/22
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Hello,
I had this exact problem, and I solved it using this package.

https://pypi.org/project/django-user-agents/

Cheers.

On Sun, Mar 20, 2022 at 7:01 PM Django2021 <dljons...@gmail.com> wrote:
Thanks for your answers.
Rephrasing question in another thread.
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