How can I get this result?

[aroni...@gmail.com]

[{'key1':a , 'key2': b},{'key1':c , 'key2': d}]

a,b

c,d

[Shai Efrati]

assuming:
l = [{'key1':a , 'key2': b},{'key1':c , 'key2': d}]

for e in l:
for k, v in iteritems(e):
print v,
print

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[Shai Efrati]

sorry.

assuming:
l = [{'key1':'a' , 'key2': 'b'},{'key1':'c' , 'key2': 'd'}]

for e in l:

for k, v in e.iteritems():
print v,
print

[Krishnasagar Subhedarpage]

Hi,

consider two objects, 

ls_dic=[{'key1':a , 'key2': b},{'key1':c , 'key2': d}]

num=sum([len(x.values()) for x in ls_dic])

print '%s' % ','.join(sorted(sum([x.values() for x in ls_dic],[])))[:-num]

print '%s' % ','.join(sorted(sum([x.values() for x in ls_dic],[])))[num:]

This is will help a lot. 

ls_dic list object is considered for input. I used num object to store number of values in each directory item of ls_dic list. This object is used in further 2 print statements. These statements will print in expected output fashion. Check it out.

Enjoy!!!!! 

 

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--

Krishnasagar S. Subhedarpage
India