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-- Eric Rexstad Research Unit for Wildlife Population Assessment Centre for Research into Ecological and Environmental Modelling University of St. Andrews St. Andrews Scotland KY16 9LZ +44 (0)1334 461833 The University of St Andrews is a charity registered in Scotland : No SC013532



Adding to Eric’s comment, the method he describes is the cue-count method. In standard point transect sampling, conceptually, recording at a point is a ‘snapshot’ – that is, instantaneous. The method gives upwardly-biased density estimates if birds are moving around during the period spent recording at a point. For a discussion of this issue and how to avoid this bias, see
Buckland, S.T. 2006. Point transect surveys for songbirds: robust methodologies. The Auk 123, 345-357.
Steve Buckland
To add another question for the same R script (above was talking about input file for ds), for my dht2 output the 'Area' is coming out as the individual area for each region whereas the 'CoveredArea' is presented as the total, meaning my abundance estimates are lower than the actual sample since the covered area is greater than the total.
To view this discussion on the web visit https://groups.google.com/d/msgid/distance-sampling/DBAPR06MB6694226BB8E5CF0D7DE26CF0EA702%40DBAPR06MB6694.eurprd06.prod.outlook.com.
On 2 Oct 2024, at 02:52, Stephen Buckland <st...@st-andrews.ac.uk> wrote:
<image001.png>
The density estimate (1.023) is the same as published in Buckland (2006):
<image002.png>
How was that estimate derived:
Estimated birds in the covered area = birds detected / detection probability = 117/0.47 = 248.9
Estimated density = estimated birds in covered area / covered area
Covered area = number points * number visits * pi * (truncation distance)^2 / (meters per hectare) # unit conversion
Covered area = 32 points * 2 visits * 3.14159 * (110m)^2 / 10000
Covered area = 243.28 hectares # note this covered area is much larger than the size of the study area
Estimated density = 248.9 birds / 243.28 hectares = 1.02 birds per hectare
Does this relieve your anxiety?
An aside: having 4 replicate point transects (spatial replicates) visited 80 times is not going to produce terribly robust estimates. Temporal replication (repeated visits) is not a substitute for spatial replication. Encounter rate variance (one component of uncertainty in density estimation) is computed on the basis of variability between spatial replicates. Having a small number of spatial replicates leads to poor estimates of this encounter rate variance. A better survey design to employ in the future is to have more spatial replicates visited fewer times, resulting in more reliable estimates with effectively the same sampling effort.
From: distance...@googlegroups.com <distance...@googlegroups.com> on behalf of Rebecca <rmaca...@gmail.com>
Sent: 30 September 2024 20:35
To: distance-sampling <distance...@googlegroups.com>
Subject: Re: [distance-sampling] how to analyze repeated point counts in Distance
To add another question for the same R script (above was talking about input file for ds), for my dht2 output the 'Area' is coming out as the individual area for each region whereas the 'CoveredArea' is presented as the total, meaning my abundance estimates are lower than the actual sample since the covered area is greater than the total.
<image003.png>
You would input the cue rate as the average (across the monitored individuals) and standard error, rather than enter each monitored individual. For the individuals that you include in your cue rate estimation, you need to be able to detect all songbursts (or calls) within the time that you monitor them. Try reading up on the method, either in the 2006 Auk paper, or the 2015 distance sampling book. The book covers more issues, so would be the better option. I’ll send you off-list the Auk paper.
Steve Buckland
Auk paper attached.

Adding to that, how you define a cue depends on the species. In my case, for three of the species, it was a ‘songburst’ – a single bout of song followed by a period of silence. In the case of the European robin, its song can go on for an extended period, but it is made up of song ‘phrases’, so each phrase was taken as a cue. That explains the higher cue rate for that species. Carrion crows in the UK typically give 3 calls in quick succession, so if I was applying the method to them, I would take the set of 3 calls to be a single cue.
Steve Buckland

On 10 Oct 2024, at 01:13, Eric Rexstad <Eric.R...@st-andrews.ac.uk> wrote:
Rebecca
The cue rates (and their standard errors) for all four species are found in Table 1 of Buckland (2006)
<image.png>
I believe that the rate in the paper is cues per 5mins, which was the time spent at each point. The rate in the example will be the rate per minute. Effort would be number of 5-min periods in the first case, and number of minutes in the second. Both ways of analysing the data will give the same estimate.
You must record cue rate for a representative sample of birds. Do not record just when they’re singing – it must be an average across birds. If for example you’re estimating number of territories of a songbird, with an assumed 1 male per territory, you would need to select a representative sample of territories, and record for a pre-determined time period. That doesn’t need to be a long time period. Because different individuals may have different cue rates, monitoring a number of birds, each for a short period, is preferable to monitoring a few birds, each for a long period.
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Additionally, when determining cue rate, should I record for a full hour and then divide by 60 to get the cues per minute (meaning less commonly heard species would have a lower cue rate) or just count cues made whilst singing?
Many thanks again,
Rebecca
From: Rebecca MacArthur <rmaca...@gmail.com>
Sent: 10 October 2024 15:10
To: Eric Rexstad <Eric.R...@st-andrews.ac.uk>
Cc: Stephen Buckland <st...@st-andrews.ac.uk>; distance-sampling <distance...@googlegroups.com>
Subject: Re: [distance-sampling] how to analyze repeated point counts in Distance
Thank you, that is what I had thought but in this table the winter wren cue rate is noted as 7.28 whereas in the distance software analysis example it is noted as 1.4558 and the standard error also decreases. I was wondering why this changes as I thought it was the same example.
