% % extract label, truncation, occlusion
% lbl = C{1}(o); % for converting: cell -> string
% objects(o).type = lbl{1}; % 'Car', 'Pedestrian', ...
% objects(o).truncation = C{2}(o); % truncated pixel ratio ([0..1])
% objects(o).occlusion = C{3}(o); % 0 = visible, 1 = partly occluded, 2 = fully occluded, 3 = unknown
% objects(o).alpha = C{4}(o); % object observation angle ([-pi..pi])
%
% % extract 2D bounding box in 0-based coordinates
% objects(o).x1 = C{5}(o); % left
% objects(o).y1 = C{6}(o); % top
% objects(o).x2 = C{7}(o); % right
% objects(o).y2 = C{8}(o); % bottom
%
% % extract 3D bounding box information
% objects(o).h = C{9} (o); % box width
% objects(o).w = C{10}(o); % box height
% objects(o).l = C{11}(o); % box length
% objects(o).t(1) = C{12}(o); % location (x)
% objects(o).t(2) = C{13}(o); % location (y)
% objects(o).t(3) = C{14}(o); % location (z)
% objects(o).ry = C{15}(o); % yaw angle
But this included info related to the 3D element of the object that I don't know what to do with. If you work this out I would be grateful to hear what you find.
John