Followup-tto sci.math
On 12/2/2022 6:13 AM, WM wrote,
responding to Jim Burns schrieb am Donnerstag,
1. Dezember 2022 um 21:01:47 UTC+1:
> Useless stuff.
>
> I have reported your last useful statement in
> de.sci.mathematik as the seventh counter-argument:
>
> 7) Bob does not step out of the matrix.
> Insisting that Bob either stays in the matrix
> or steps out of the matrix is insisting on
> Bob-conservation. The set of all exchanges
> does not have Bob-conservation.
> [J. Burns,
>
https://groups.google.com/g/sci.math/c/LHEV4iqs5bM]
>
> Bob
> {{Abkürzung für das zuerst auf dem Bruch 1/2
> liegende O}}
> tritt nicht aus der Matrix heraus.
> Darauf zu bestehen, dass Bob entweder
> in der Matrix bleibt oder
> aus der Matrix heraustritt,
> bedeutet auf Bob-Erhaltung zu bestehen.
> Die Menge aller Vertauschungen hat
> keine Bob-Erhaltung.
Okay.
> WM:
> Darauf zu verzichten,
> dass Bob entweder in der Matrix bleibt
> oder aus der Matrix heraustritt,
> bedeutet einen Verzicht auf Logik.
<WM>
| To forgo Bob either staying in the Matrix
| or stepping out of the Matrix is
| to forego logic.
|
|
https://translate.google.com
There is a more-common, less-amusing term for
"Bob-conservation". I have reasons for not using it.
A set (collection) has _Bob-conservation_
if and only if
there is no match of its elements to
a proper (unequal) subset or to a proper
superset.
A FISON
-- Finite Initial Segment Of Naturals --
is a totally-ordered set (collection) which
begins at 0
ends somewhere
and for which, for each split,
there is some i last-before that split
with its successor i⁺⁺ first-after that split.
| ∀i : i⁺⁺ ≠ 0
| ∀i, ∀j ≠ i : i⁺⁺ ≠ j⁺⁺
For each FISON, there is a unique FISON-end.
For each FISON-end, there is a unique FISON.
Because of that match of FISON to FISON-ends,
FISON-ends can be used to represent FISONs, and
FISONs can be used to represent FISON-ends.
Assuming that, by "dark number", you mean
something not in any FISON,
each element of the set of all FISON-ends
is not a dark number.
FISON-ends are what are usually meant by
"natural number" but (we see) FISONs could serve
as representations of natural numbers as well.
<JB>
> Insisting that Bob either stays in the matrix
> or steps out of the matrix is insisting on
> Bob-conservation. The set of all exchanges
> does not have Bob-conservation.
Each FISON has Bob-conservation.
It has no match to any other FISON.
Each set which matches some FISON has
Bob-conservation.
It has no match to any proper subset or
proper superset.
It has no match to any other FISON.
However,
the set of all FISONs and
the set of all FISON-ends
have matches to proper subsets and
to proper supersets.
There can be matches between a set with Bob
and a proper subset, a set without Bob.
These sets do not have Bob-conservation.
Also, recalll that
these sets have no dark numbers.
Therefore,
"their dark numbers" is not the reason
that they do not have Bob-conservation.