Curvilinear Regression (Cubic)

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sagar gaikwad

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May 17, 2021, 9:20:18 PM5/17/21
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Respected Neeraj Sir and Group Members, 


In the curvilinear regression how to interpret the result of cubic curve relationship. The value of Durbin Watson is not generated, and the coefficients are found to be insignificant, how to make a regression model in such cases.

 

image.png

 

 

 

Thanks & Regards,
Mr. Sagar Gaikwad
Assistant Professor & Ph. D Coordinator
Vidyalankar School of Information Technology
Mob No: 9833376766
ORCID ID : 0000-0002-3816-2801

Neeraj Kaushik

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May 18, 2021, 3:52:39 AM5/18/21
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Dear Sagar
Plz aware of why you are using the Curvilinear regression?
Best wishes

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sagar gaikwad

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May 18, 2021, 4:03:36 AM5/18/21
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Respected sir, 

I am using curvilinear because curve estimation suggests that linear is having low R Square value and Cubic is having good R Square value. 

Model Summary and Parameter Estimates

Dependent Variable: Work_Engagement

Equation

Model Summary

Parameter Estimates

R Square

F

df1

df2

Sig.

Constant

b1

b2

b3

Linear

.103

102.705

1

898

.000

99.169

-.606

 

 

Logarithmic

.111

111.670

1

898

.000

125.649

-13.210

 

 

Inverse

.109

110.398

1

898

.000

72.801

248.418

 

 

Quadratic

.120

60.898

2

897

.000

116.495

-2.356

.038

 

Cubic

.124

42.292

3

896

.000

87.741

1.970

-.163

.003

Compound

.099

98.458

1

898

.000

101.937

.991

 

 

Power

.106

106.045

1

898

.000

150.329

-.194

 

 

S

.104

104.241

1

898

.000

4.237

3.641

 

 

Growth

.099

98.458

1

898

.000

4.624

-.009

 

 

Exponential

.099

98.458

1

898

.000

101.937

-.009

 

 

The independent variable is Tunover_Intention.


Thanks & Regards,
Mr. Sagar Gaikwad
Assistant Professor & Ph. D Coordinator
Vidyalankar School of Information Technology
Mob No: 9833376766
ORCID ID : 0000-0002-3816-2801

Neeraj Kaushik

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May 18, 2021, 4:05:02 AM5/18/21
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Plz re-run the model by opting not to take construct in the model
If the IDV is still not significant then use Linear regression.

sagar gaikwad

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May 18, 2021, 4:34:53 AM5/18/21
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Respected sir,

Great input sir,

By not opting constant in the model, IDV are found to be significant in curvilinear cubic. Can this model without constants be a good model. 

 

image.png

 

 

Thanks & Regards,
Mr. Sagar Gaikwad
Assistant Professor & Ph. D Coordinator
Vidyalankar School of Information Technology
Mob No: 9833376766
ORCID ID : 0000-0002-3816-2801

Neeraj Kaushik

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May 18, 2021, 4:38:43 AM5/18/21
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A Quadratic model seems a better solution here.
Model without Intercept indicates that when x=0, y=0
It means that the regression line is passing through the origin. 

sagar gaikwad

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May 18, 2021, 4:47:37 AM5/18/21
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Respected sir,

Thank you so much. Many doubts are cleared today. Thank you again.
Good day sir. 


Thanks & Regards,
Mr. Sagar Gaikwad
Assistant Professor & Ph. D Coordinator
Vidyalankar School of Information Technology
Mob No: 9833376766
ORCID ID : 0000-0002-3816-2801

Dr. Nisha Arora

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May 25, 2021, 12:12:50 AM5/25/21
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Hi Sagar,
I would like to add something to the discussion.
1. Seems like you have just one predictor (case of simple regression). Scatter plot will give you insight into the type of relationship. Always start the analysis by exploring and understanding your data. And also see what does the theory says about your variables?
2. Did you check for model assumptions? Is RSE 20 acceptable? which model evaluation matric you need? [This question usually scholars ignore as they always refer to R sq and Adj R sq, maybe you can leave it too]
Always perform post estimation analysis _ Using plots and/or tests. [R is great for these but we can very well do this in SPSS too]
And make changes if required.
3. To compare different models, R has great functionalities [anova() function and many more. See the screenshot below. Or you may find some reference code on my GitHub page]
Maybe you can do this manually in SPSS.
4. Removing intercept has its own consequences, keep in mind those.



--
r code_compare models.png
r output_model performance.png

sagar gaikwad

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May 25, 2021, 3:11:21 AM5/25/21
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Dear Dr. Nisha Madam

Thank you so much for your insights on my query. 

1. I have performed curve estimative in SPSS to understand the relationship between two variables. I have used the model whose R is greater 
2. I have checked R square and Adj R Square for the model suggested in curve estimation. Please guide how to check RMSE in SPSS for a regression model.
3. I have checked R when I have performed  curve estimation in SPSS for all the types of relationship. 
4. Agree madam, Skipping constant in the regression model is not a good option. 

Please guide further if I am wrong in the above statements. 


Thanks & Regards,
Mr. Sagar Gaikwad
Assistant Professor & Ph. D Coordinator
Vidyalankar School of Information Technology
Mob No: 9833376766
ORCID ID : 0000-0002-3816-2801

Dr. Nisha Arora

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May 26, 2021, 2:17:37 AM5/26/21
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Hi Sagar,
Seems like you couldn't understand the points shared by me. However, you are correct in your observations, you can proceed as suggested by Neeraj Sir.
Theoretically, RSE (Residual standard error) is different from RMSE (Root Mean Square Error).
RSE (you get in output of lm() function in R directly) tells you how much your average response will deviate from the regression line or how far are your predictions?

SPSS uses 'Standard error of Estimate' to represent RMSE and hence the confusion.
and Book: Introduction to Statistical Learning with R

image.png


Sagar Gaikwad

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May 26, 2021, 3:53:34 AM5/26/21
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Respected Madam,

Thank you so much for the clarification. Just now I watched a video on how to calculate Standard error of Estimate in SPSS. 


Thanks & Regards,
Mr. Sagar Gaikwad
Assistant Professor & Ph. D Coordinator
Vidyalankar School of Information Technology
Mob No: 9833376766
ORCID ID : 0000-0002-3816-2801

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