How to download D3 documentation for offline viewing

[Stanley Gu]

Is there an easy way to download the D3 documentation and/or the examples for offline viewing?

[Zack Maril]

git clone https://github.com/mbostock/d3.wiki.git

[Stanley Gu]

Thanks, I learned a little bit more after reading this: https://github.com/blog/699-making-github-more-open-git-backed-wikis.

However, the examples gallery links out to http://bl.ocks.org/, how can I get local copies of all the blocks?

[d3noob]

There are several suggestions here; https://groups.google.com/forum/?fromgroups=#!topic/d3-js/FCespD5yxcw or there is a free pdf of 'how to' type stuff for d3.js on d3noob.org here http://www.d3noob.org/p/d3noob-downloads.html (there are also some example files to go along with the document).

[Chris Viau]

Since bl.ocks is a Gist viewer, you could use the Gist API to download all of Mike Bostock gists, where all the examples resides. 

[Amara Balakrishna]

 var dataArray = [30,40,50];

                 var canvas = d3.select("body")

                                .append("svg")

                                .attr("width",1000)

                                .attr("height",3500);

                 var circle = canvas.selectAll("circle")

                                .data(dataArray)

                                .enter()

                                      .append("circle")

                                      .attr("cx",function(d,i){ return d * 10;})

                                      .attr("cy",function(d,i){ return d * 5;})

                                       .attr("r",function(d,i){ return d;})

          circle.transition().delay(1500)

                .duration(2000)

                .attr("cy",500)

                .transition()

        .duration(2000)

        .attr("cy",50) .transition()

                  .duration(2000)

                  .attr("cx",500)

    .attr("cy",50) .transition()

            .duration(2000)

            .attr("cx",00)

i made this code what i want is make this as continuous loop.is it possible.