Naive Bayes norm function

[Tazin Afrin]

The function is :

function norm(x,m,s) {
    return 1/sqrt(2*pi*s^2)*e^(-1*(x-m)^2/(2*s^2))
}

And the inputs are 

m = mean

s = standard deviation

x = the value we are trying to score

In the example,  f(temperature=66|yes) = norm(73,6/2,66) =0.0340 , are the arguments in right order? I do not understand how the output is 0.0340, why the input for sd is 6/2 not 6.2 ? 

And in the function, is it (1/sqrt)*e or 1/(sqrt*e) ?

- Tazin

[Tim Menzies]

thanks*1000 for your query. please keep'em coming!

apologies from me- there are typos in the example. it should be

norm(66, 73, 6.2) = 0.0340

as to your other query, here's the function, with the algebra written
more clearly, and all the constants explicitly defined:

function norm(x,m,s) {
pi= 3.1415926535
e = 2.7182818284
a = 1/sqrt( 2*pi*s^2 )
b = (x-m)^2 / (2*s^2)
return a * e ^ (-1*b)

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[Tazin Afrin]

Thank you :)

 - Tazin