Fwd: Please solve this qs.

[Sakshi Vaid]

---------- Forwarded message ----------
From: Sakshi Vaid <sakshi...@gmail.com>
Date: Sat, Apr 9, 2011 at 4:34 PM
Subject: Please solve this qs.
To: csmy...@googlegroups.com

An aircraft is equipped with three engines that operate independently.A probability of an engine is 0.01.What is the probability of successful flight if only one engine is needed for successful operation of flight?

[praveen]

It should be 0.01+0.01+0.01=.03 I guess

> flight if only one engine is needed for successful operation of flight?- Hide quoted text -
>
> - Show quoted text -

[Anju Grewal]

Hey...plz clarify wots does probability of one engine stands for...for wht is the prob. given?

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Thanks & Regards

Anju Grewal

[Rudra Alok]

P = 1-Q

   = 1- 0.01  => 0.99

[joshna harinath]

Hi i think the probability of the successful flight is 0.01 (Provided the probability of each engine is 0.01)

 

Correct me if im wrong

 

Regards

Joshna

[Anju Grewal]

Exactly...i agree with joshna...:-)

[Rudra Alok]

If this is the answer .... one should have following conclusions:

(kindly go for the options in lighter mood)

1. You should not fly at all .... 

2. max. no of people who are weak in mathematics resort for CS course.

3. Maths is not everybody game/riddle

As per my understanding, the person who has asked the question --

1. If a qualified CS -- must be preparing for CWA

2. If still a CS student .. must be taking CA entrance course. 

anyways ... hope for more imaginative answers. 

Njoi ..... Regards: Alok    

[Anju Grewal]

:-)..............gud one.....:-) but whteva...tell me the correct answer...thatsit...:-)

[Rudra Alok]

answer is already there .... ;)

[Anju Grewal]

Well, if only one engine is needed for the aircraft to successfully complete its flight, the probability P of a successful flight is very simple. The probability Q of all three engines to fail is 0.01^3. The probability P is then P = 1 - Q

1 - 0.01 = 0.999999

So, I agree........:-)

[Anju Grewal]

Dear All,

Though it is not clearly mentioned, I am assuming 0.01 is the probability of successful operation for an engine. So probability of non-successful operation of an engine = 1 - 0.01 = 0.99 i.e. probability that none of the engine is operating successfully = 0.99³ = 0.970299. 
Hence the required probability that at least one of the engine operates successfully for successful operation of aircraft = 1 - 0.970299 =0.029701 

I guess i must be clear to all now....;-)

On Mon, Apr 11, 2011 at 3:34 PM, Anju Grewal <csanju...@gmail.com> wrote:

and i was not a weak maths student....infact a good one i was...its all happnd jst bcoz v don't have maths in b.com or cs. 

[Anju Grewal]

Dear All,

Though it is not clearly mentioned, I am assuming 0.01 is the probability of successful operation for an engine. So probability of non-successful operation of an engine = 1 - 0.01 = 0.99 i.e. probability that none of the engine is operating successfully = 0.99³ = 0.970299. 
Hence the required probability that at least one of the engine operates successfully for successful operation of aircraft = 1 - 0.970299 =0.029701 

I guess i must be clear to all now....;-) lols now set those conclusions....:-p ;-)

On Mon, Apr 11, 2011 at 2:50 PM, Rudra Alok <rudr...@gmail.com> wrote:

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[Rudra Alok]

Again and again .... same email ... expecting some comments form my side ??

[Anju Grewal]

Neah not at all.....there was um prb. on gmail so can't  c that mail in this thread thatsy....Don't worry I don't need ur comments....:-) I jst want a correct answer whether its from ur side or anyone else...doesn't matters at all....wot matters was jst the ryt ans...:-)

[praveen]

Actually
The plain has 3 engines and the probability of one single engine
functioning correctly is 0.01,
the question is what is the probability of a sucessul flight
The event of sucessful flight can be defined this way here in this
case=Either engine 1 functioning correctly ( or ) engine 2 functioning
correctly ( or )engine 3 functioning correctly
"OR" in probability means addition "and"means multiplication
So the probability of sucessful flight =0.01+0.01+0.01=0.03
Had the question been all the three engines are required to
succesfully operate the flight
answer would be =0.01*0.01*0.01=0.000001

On Apr 9, 4:28 am, Sakshi Vaid <sakshicont...@gmail.com> wrote: