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Is it sufficient for full marks to find an algorithm that is O(k n log
n), given that a) this algorithm is an heuristic and b) for a multiple
sequence alignment, k << n is a requisite for an informative
resolution?
Michael Brudno
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Nov 18, 2010, 6:09:32 PM11/18/10
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I am expecting a non-heirustic algorithm that is O(n^2). Anything more is bonus.