Assignment 0

[Aaron Albers]

Hey everyone,

Thanks for joining the group. Just curious to know if everyone has
started the first homework or not.

Aaron

[Aaron Albers]

This homework is due on Tuesday right?

[Aaron Albers]

1.a) n is even -> n^2 + 3n is even

n is even iff n = 2k, therefore

n^2 + 3n = (2k)^2 + 3(2k) = 4k^2 + 6k = 2(2k^2 + 3k) -> n^2 + 3n is even

1.b) converse: n^2 + 3n is even -> n is even

n is odd iff n = 2k + 1, therefore

n^2 + 3n = (2k +1)^2 + 3(2k + 1) = 4k^2 + 10k + 4 = 2(k^2 + 5k + 2) -> n^2 = 3n is even when n is odd (ie 2k + 1)

So the converse of (a) is not true.

[Aaron Albers]

EDIT

2(k^2 + 5k + 2) should be 2(2k^2 + 5k + 2)

[Anne S]

Yes, it is due on Tuesday. I'm about half done.

- Anne

On Sep 6, 12:13 am, Aaron Albers <aaroncalb...@gmail.com> wrote:
> This homework is due on Tuesday right?
>

[Aaron Albers]

Cool. Feel free to agree or disagree with the solutions I present and contribute your own. =)