Assignment 1 : Problem 2

[Aaron Albers]

For n  , let An = {a   | a <= n }

(b) A3  A-3

(c) A3  (A-3)^c

(d) ^4 Ai

[Aaron Albers]

(b) A3  A-3

This would go from -3 to 3

 A3  A-3 = {-3, -2 -1, 0, 1, 2, 3}

[Aaron Albers]

I take it back.

The only intersection that A3  A-3 has is -3 to -infinity

A3  A-3 = {a   | a <= -3 }

[Aaron Albers]

(d) ^4 Ai = A0  A1  A2  A3  A4 =  {a   | a <= 0 }

On Tue, Sep 14, 2010 at 9:05 PM, Aaron Albers <aaronc...@gmail.com> wrote:

[Aaron Albers]

(c) A3  (A-3)^c = A3 \ A-3 = { -2, -1, 0, 1, 2, 3 }

On Tue, Sep 14, 2010 at 9:05 PM, Aaron Albers <aaronc...@gmail.com> wrote:

[alex]

wouldn't this be from -∞ to -3.  since a ≤ n

[alex]

i spoke too early. i just read your next posting. goodness i need to read all of it before i post anything redundant. 

[Anne S]

Hey Aaron -- there are tags in your post that don'g seem to be coming
through for me. For example [image: \cap \!\,] Are you sending images
in your messages?

On Sep 14, 9:28 pm, Aaron Albers <aaroncalb...@gmail.com> wrote:
> I take it back.
>
> The only intersection that A3 [image: \cap \!\,] A-3 has is -3 to -infinity
>
> A3 [image: \cap \!\,] A-3 = {a [image: \in \!\,] [image: \mathbb{Z} \!\,] |
> a <= -3 }
>

> On Tue, Sep 14, 2010 at 9:07 PM, Aaron Albers <aaroncalb...@gmail.com>wrote:
>
> > (b) A3 [image: \cap \!\,] A-3
> >  This would go from -3 to 3
>
> >  A3 [image: \cap \!\,] A-3 = {-3, -2 -1, 0, 1, 2, 3}
>

[Diane]

Anne,

If you open the emails google groups sends out, you can select show
images and it becomes much more readable.

[anne speck]

Much better! Thank you!