2. summation value = n(n+1)/2; value in theta notation=Θ(n2)
3. summation value = n(n+1)(2n+1)/6; value in theta notation = Θ(n3)
4. summation value = n2(n+1)2/4 ; value in theta notation = Θ(n4)
5. B
6. T is always a spanning tree but not necessarily minimal
7. True
8. True
9. True
I will post the work tomorrow night..