A problem, from the top of my head.

[Jan Monterrubio]

the method, duplicateStrings takes two String arrays. 

It compares how many of the strings in the first array are equal to the strings in the second array and 

counts the number of strings that are in both.

public int duplicateStrings(String[] arr1, String[] arr2);

-> write this method

For 

String[] arr1 = {"ABC", "DEF", "GH", "IJ"};

String[] arr2 = {"AB", "DEF", "IJ", "GH"};

I got 3.

Your method should be shorter than 10 lines.

 

[Kalen Miller]

Think this works:

public

static int duplicateStrings(String[] arr1, String[] arr2){

int count = 0;

if(arr1.length < arr2.length)duplicateStrings(arr2,arr1);

for(int i = 0; i<arr1.length; i++){

for(int j = 0; j<arr2.length; j++){

if(arr1[i].equals(arr2[j]))count++;

}

}

return count;

}

--
Gunner

[Kalen Miller]

Not sure why I decided to add if(arr1.length < arr2.length)duplicateStrings(arr2,arr1);  overthinking again...

--
Gunner

[Kalen Miller]

"counts the number of strings that are in both": System.

out.println(arr1.length+arr2.length);

--
Gunner

[Jan Monterrubio]

Why not a for each loop?

 

---

Date: Thu, 5 May 2011 21:15:21 -0600
Subject: Re: A problem, from the top of my head.
From: gunne...@gmail.com
To: cs251-...@googlegroups.com

[Kalen Miller]

for

(String a : arr1){

    for(String b : arr2){

        if(a.equals(b))count++;

--
Gunner