Left operators

[Bill Hart]

Is there a way to define left operators, i.e. suppose you have defined a class C and you want to define a multiplication operator for C which handles the expression

a * c

where a is an int say, and c is of type C?

I can currently only work out how to define right multiplication, and left multiplication does not appear to be rewritten as right multiplication (of course you wouldn't want this for subtraction anyway).

Bill.

[Michael Muller]

Bill Hart wrote:
> Is there a way to define left operators, i.e. suppose you have defined a
> class C and you want to define a multiplication operator for C which
> handles the expression
>
> a * c
>
> where a is an int say, and c is of type C?

Yes, "oper <binop>" has an "r" modifier:

class X { X oper r+(int i) { return this } }
X x = {}; import crack.io cout; cout `$(100 + x)\n`;

We actually refer to this as "right" multiplication, though, referring to the
location of "this" in the expression (and copying python's __rmul__, __radd__
...)

>
> I can currently only work out how to define right multiplication, and left
> multiplication does not appear to be rewritten as right multiplication (of
> course you wouldn't want this for subtraction anyway).
>
> Bill.
>

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[Bill Hart]

On 17 September 2013 18:50, Michael Muller <mmu...@enduden.com> wrote:

Bill Hart wrote:
> Is there a way to define left operators, i.e. suppose you have defined a
> class C and you want to define a multiplication operator for C which
> handles the expression
>
> a * c
>
> where a is an int say, and c is of type C?

Yes, "oper <binop>" has an "r" modifier:

  class X { X oper r+(int i) { return this } }
  X x = {}; import crack.io cout;  cout `$(100 + x)\n`;

Thanks!

 

We actually refer to this as "right" multiplication, though, referring to the
location of "this" in the expression (and copying python's __rmul__, __radd__
...)

I probably do too, but I always get these mixed up.

Bill.